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Artemon [7]
3 years ago
8

A boy accidentally touch an electric cable and quickly withdrew his hand. Narrate the impulses involved in such action.

Physics
2 answers:
Lelechka [254]3 years ago
3 0

Answer:

Quick action was in this as a thought of he knew he could die from this

Stels [109]3 years ago
3 0

Answer:

The correct answer is because of the current.

Explanation:

A boy accidentally touched an electric wire and quickly withdrew his hand. This is because having contact with an electric wire causes a tingling sensation. This causes the person to quickly remove the hand from the wire. The impulse is produced by a contraction of the nervous system. If you grasp the cable with the palm of your hand, it will close and be attached to the cable.

Have a nice day!

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6 0
3 years ago
Two resistances, R1 and R2, are connected in series across a 12-V battery. The current increases by 0.500 A when R2 is removed,
KATRIN_1 [288]

Answer:

a)   R₁ = 14.1 Ω,   b)  R₂ =  19.9 Ω

Explanation:

For this exercise we must use ohm's law remembering that in a series circuit the equivalent resistance is the sum of the resistances

all resistors connected

           V = i (R₁ + R₂)

with R₁ connected

           V = (i + 0.5) R₁

with R₂ connected

           V = (i + 0.25) R₂

We have a system of three equations with three unknowns for which we can solve it

We substitute the last two equations in the first

           V = i ( \frac{V}{ i+0.5} + \frac{V}{i+0.25} )

           1 = i ( \frac{1}{i+0.5} + \frac{1}{i+0.25} )

           1 = i ( \frac{i+0.5+i+0.25}{(i+0.5) \ ( i+0.25) } ) =  \frac{i^2 + 0.75i}{i^2 + 0.75 i + 0.125}

           i² + 0.75 i + 0.125 = 2i² + 0.75 i

           i² - 0.125 = 0

           i = √0.125

           i = 0.35355 A

with the second equation we look for R1

          R₁ = \frac{V}{i+0.5}

          R₁ = 12 /( 0.35355 +0.5)

          R₁ = 14.1 Ω

with the third equation we look for R2

          R₂ = \frac{V}{i+0.25}

          R₂ =\frac{12}{0.35355+0.25}

          R₂ =  19.9 Ω

3 0
2 years ago
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