How are the rates 6 pounds per day and 6 days per pound difference? When would each be useful
1 answer:
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The first thing you should know is that you need three points to be able to graph a second degree equation.
You can create a table and plot several points to obtain the parabola
In this case we will use a computational tool called wolfram alpha
Answer:
See attached image.
The graph is shown for two different intervals of the domain.
You can create a table and plot several points to obtain the parabola
In this case we will use a computational tool called wolfram alpha
Answer:
See attached image.
The graph is shown for two different intervals of the domain.
Answer:
The systems of equation are .
Vanessa worked for<u> 6 hrs </u>and Geneva worked for <u>15 hrs</u> to earn exactly $240.
Step-by-step explanation:
Let the number of hours worked by Vanessa be 'v'.
Let the number of hours worked by Geneva be 'g'.
Given:
Total number of hours worked = 21 hours
So we can say that;
Total number of hours worked is equal to sum of number of hours worked by Vanessa and number of hours worked by Geneva.
framing in equation form we get;
⇒ equation 1
Also given:
per hour earnings of Vanessa = $10
per hour earning of Geneva = $12
Total they need to earn = $240
So we can say that;
Total they need to earn would be equal to sum of per hour earnings of Vanessa multiplied by number of hours worked by Vanessa and per hour earning of Geneva multiplied by number of hours worked by Geneva.
framing in equation form we get;
⇒ equation 2
Hence The systems of equation are .
On Solving above equations we get;
First we will multiply equation 1 by 10 we get;
⇒ equation 3
Now Subtracting equation 3 from equation 2 we get;
Dividing both side by 2 we get;
Now Substituting the value of g in equation 1 we get;
Hence Vanessa worked for<u> 6 hrs </u>and Geneva worked for <u>15 hrs</u> to earn exactly $240.