All categories

3 years ago

Can you answer it ????,(^^)

Engineering

2 answers:

Fittoniya [83]3 years ago

6 0

$\longmapsto\tt{8}$

blagie [28]3 years ago

5 0

Answer:

answer is 8 sheep's are left

You might be interested in

PLEASE HELP ME!!!!!! IM LOW ON POINTS BUT I NEED SOME HELP, QUICK!!! POINTS FOR HELPFUL ANSWERS + BRAINLIEST!!!!!

meriva

Answer:

Kitchen sinks can be clogged for a few reasons, food hair, and other things. Overtime, buildup of these things lead to clogging.

A few methods to fix clogging are, baking soda mixture, plunging, and boiling water.

The first method, baking soda mixture, what you do is you pour a cup of baking soda and vinegar down the drain, and place a rubber stopper to cover the drain opening. Wait 10 or more minutes, and take out the stopper, and run hot tap water until it's unclogged.

The second method is plunging. Make sure the sink has enough water to submerge the plunger, and start plunging. While you are plunging, maintain a good seal to get the best results. This usually works, but sometimes it doesn't.

The last method is boiling water. Pour boiling water into the drain, then after a while, the clogged drain should unclog, if it doesn't repeat the process until necessary.

Explanation:

8 0

3 years ago

An 18-in.-long titanium alloy rod is subjected to a tensile load of 24,000 lb. If the allowable tensile stress is 60 ksi and the

Vilka [71]

Answer:

Required Diameter = 302.65 inches

Explanation:

We are given;

Allowable tensile stress = 60 ksi

Weight of tensile load = 24,000 lb

Elongation = 0.05 in

Original length = 18 in

We'll need to check the diameters under stress and strain.

Now, we know that the formula for stress is;

Stress = Force/Area

Thus,

Area = Force/stress

So for this stress, area required is;

A_req = 24000/60 = 4000 in²

So let's find the required diameter here.

Area = πd²/4

So, 4000 = πd²/4

(4000 x 4)/π = d²

d² = 5092.96

Required diameter here is;

d = √5092.96

d = 71.36 in

For Strain;

Formula for strain is;

Strain = stress/E

We are given E = 120 ksi

stress = P/A = 24,000/A

strain = elongation/original length = 0.05/18 = 0.00278

Thus;

0.00278 = P/(A•E)

0.00278 = 24000/(120 x A)

Making A the subject to obtain;

A = 24000/(120 x 0.00278)

A_required = 71942 in²

Area = πd²/4

So, 71942 = πd²/4

(71942 x 4)/π = d²

d² = 91599.4

Required diameter here is;

d = √91599.4

d = 302.65 in

The larger diameter is 302.65 inchesand it's therefore the required one.

3 0

4 years ago

What is the tolerance of number 4?

Kamila [148]

Answer:

Answer: ±0.02 units or 20±0.02 units or 19.98-20.02 units depending on how they prefer its written (typically the first or second one)

Explanation:

says on the sheet. Unless otherwise stated 0.XX = ±0.02 tolerance

(based on image sent in other post)

5 0

3 years ago

The diffusion coefficients for iron in nickel are given at two temperatures:T (K)D (m2/s)12739.4 × 10–1614732.4 × 10–14(a) Deter

hram777 [196]

Answer:

The diffusion coefficients for iron in nickel are given at two temperatures:

T (K) 1273 1473

D ( $m^{2}$ /s) 9.4 × $10^{-16}$ 2.4 × $10^{-14}$

(a) Determine the values of Do and the activation energy Qd.

(b) What is the magnitude of D at 1100°C (1373 K)?

A

The pre-exponential factor Do = 2.1 x $10^{-16}$

The activation energy Qd = 252,609 J/mol

B

The diffusion coefficient D= 5.14 x $10^{-15}$

Explanation:

The full explanation is contained in the attached images;

5 0

4 years ago

What do auto mechanics do when they take out the spark plugs

ivanzaharov [21]

Check them to see if the cylinder is running rich or lean. This can be determined by looking at the electrodes on the plugs
Hope this helps.

7 0

3 years ago

Can you answer it ????,(^^)​

Can you answer it ????,(^^)