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stiks02 [169]
3 years ago
5

The Egyptians and Greek shared which belief about preparing for important dreams

Physics
2 answers:
Mamont248 [21]3 years ago
8 0
<span>Both the Egyptians as well as the Greeks had viewed favourably the inclusion of dreams in our daily life and had an interest in them which dictated their desire to learn about them.</span>
Alchen [17]3 years ago
8 0

Answer:

B. Dream preparation increased the likelihood of getting the right dream.

Explanation:

got it right on the quiz.

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W=225 J<br> P=25 W<br> t=?<br> what's T
Mama L [17]

Explanation:

p=w/t

t=w/p

t=225/25=9seconds

5 0
2 years ago
__________ research is designed to measure the association between variables that are not manipulated by the researcher.
Sliva [168]

Answer:

Option c. Correlational

Explanation:

Correlational research is basically a method of carrying out a research where an experiment can not be conducted and where a researcher has to figure out that whether the two variable are in association with each other and if these are related then in what way the association between these two exists without any manipulation from the researcher's end.

It seeks to understand, measure and make assessment of the relationship or  

association between these variables but can not find out if a variable is caused by the other variable.

3 0
3 years ago
Q¹=0,07Mc Q²=2C r=1,08 cm F=.......?
Nostrana [21]
The force (F) of attraction or repulsion between two point charges (Q1 and Q2) is given by the following rule:
F = <span>(k * q1 * q2) / (r^2)  where:
</span>q1 and q2 are the charges
k is coulomb's constant = 9 x 10^9<span> N. m</span>2/ C<span>2
</span>r is the distance between the two charges.

Applying the givens in the mentioned equation, we find that:
F = (9 x 10^9<span> x 0.07 x 10^6 x 2) / (0.0108)^2 = 1.08 x 10^19 n </span> 
5 0
3 years ago
A car accelerates uniformly from rest to speed 6.6 m/s in 6.5 s .Find the distance the car travel during this time .​
kirill [66]

Answer:

<em>The distance the car traveled is 21.45 m</em>

Explanation:

<u>Motion With Constant Acceleration </u>

It occurs when an object changes its velocity at the same rate thus the acceleration is constant.

The relation between the initial and final speeds is:

v_f=v_o+at\qquad\qquad [1]

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The distance traveled by the object is given by:

\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]

Solving [1] for a:

\displaystyle a=\frac{v_f-v_o}{t}

Substituting the given data vo=0, vf=6.6 m/s, t=6.5 s:

\displaystyle a=\frac{6.6-0}{6.5}

a = 1.015\ m/s^2

The distance is now calculated with [2]:

\displaystyle x=0*6.5+\frac{1.015*6.5^2}{2}

x = 21.45 m

The distance the car traveled is 21.45 m

6 0
3 years ago
Any example of acceleration related to human body??? <br> answer quickly plz :)
Hitman42 [59]

Answer:

Acceleration stress, physiological changes that occur in the human body in motion as a result of rapid increase of speed. ... A force of 3 g, for example, is equivalent to an acceleration three times that of a body falling near Earth.

4 0
3 years ago
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