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Atomic percentages<u>: 68% of copper and 32% of nickel.</u>
How this is calculated?
The given alloy is 100 g ,
m(Cu) = 0,7 · 100 g = 70 g.
m(Ni) = 0,3 · 100 g = 30 g.
n(Cu) = m(Cu) ÷ M(Cu) = 70 g ÷ 63,546 g/mol
n(Cu) = 1,10 mol.
n(Ni) = m(Ni) ÷ M(Ni) = 30 g ÷ 58,71 g/mol
n(Ni) = 0,51 mol
n(Cu) : n(Ni) = 1,10 mol : 0,51 mol
%(Cu) = 1,1 mol ÷ 1,61 mol = 0,68 = 68 %.
Similarly, %(Ni)=32%
What are Cu-Ni alloys?
- Cu-Ni alloys are alloys of copper (base metal with the largest individual content) and nickel with or without other elements, whereby the zinc content may not be more than 1%.
- When other elements are present, nickel has the largest individual content after copper, compared with each other element.
- As with other copper alloys, it is necessary to distinguish between wrought alloys, which are processed to semi-finished products, and cast alloys, from which castings are produced by various casting processes.
To know more about Cu-Ni alloys, refer:
brainly.com/question/16856761
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Answer:
Germanium has the larger atomic radius.
Answer:
Explanation:By the time, that the balloon got too high in the sky, the pressure inside the balloon will soon overcome the pressure outside, and the balloon's elasticity is not too strong to hold the air inside, that the Helium gas inside will successfully push out the walls of the balloon and so it bursts!
The energy change when the temperature of 0.750 kg of water decreased from 123 °C to 23.0 °C is -313.5 kJ.
In this problem, we are dealing with specific heat which is referred to as the sum of heat per unit mass required to raise the temperature by one degree Celsius.Since we know the boiling point of water is 100°C, at 123°C, the water is steam.
The formula we are referring to for calculating the heat energy Q
Q= m C ΔT
where m is the mass of water which is equal to 0.750 Kg, then
C is the specific heat of water equal to 4180 J/Kg °C and
ΔT is the change in temperature which is (23-123)= -100°C
So, assembling those desired values on the formula we get,
Q= 0.750 (4180) (-100)
Q=-313500
= -313.5 kJ
To know more about specific heat refer to the link brainly.com/question/13163208?referrer=searchResults.
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