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tensa zangetsu [6.8K]
3 years ago
12

The equilibrium constant kc for the reaction hf(aq) + h2o(l) h3o+(aq) +f-(aq) is 3.5 x 10-4. what is the equilibrium concentrati

on of h3o+ if the initial concentration of hf is 1.0 m?
Chemistry
1 answer:
nataly862011 [7]3 years ago
5 0
According to the reaction equation:
          Hf(aq) + H2O (l)↔ H3O+ (aq) + F(aq)  

initial   1 m                       0           0
            -X                         +X          +X
          (1-x)                         X            X
We assumed that [H3O+] = X
so. at eqilibrium:
Kc = [H3O] [ F] / [Hf] when we have Kc so by substitution:
3.5x10^-4 = X^2 / (1-X)
∴X^2 = 3.5x10^-4 - 3.5x10^-4 X
X^2 + 3.5x10^-4 X - 3.5x10^-4= Zero
by solving this equation:
(X-1.9x10^-2)(X + 1.9x10^-2) = Zero 
∴X = 1.9x10^-2 
∴ the equilibrium constatnt of H3O = 1.9x10^-2 M
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Answer:

1.36 × 10³ mL of water.

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We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
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Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

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