Question

A magazine provided results from a poll of 1500 adults who were asked to identify their favorite pie. among the 1500 ​respondents, 12​% chose chocolate​ pie, and the margin of error was given as plus or minus3 percentage points. what values do modifyingabove p with caret​, modifyingabove q with caret​, ​n, e, and p​ represent? if the confidence level is 99​%, what is the value of alpha​? the value of modifyingabove p with caret is ▼ the value of modifyingabove q with caret is ▼ the sample size. found from evaluating 1 minus modifyingabove p with caret . the population proportion. the margin of error. the sample proportion. the value of n is ▼ the population proportion. the margin of error. the sample size. found from evaluating 1 minus modifyingabove p with caret . the sample proportion. the value of e is ▼ the margin of error. the sample proportion. the sample size. the population proportion. found from evaluating 1 minus modifyingabove p with caret .

Answer 1

The value of $\hat p$ will be the same as the percentage of the 1500 respondents who like chocolate pie. And that percentage as per the data in the question is 12%. Therefore, $\hat p$=0.12.

The value of $\hat q$ simply is $\hat q=1-\hat p$, therefore,$\hat q=1-0.12=0.88$.

The sample size is 1500. Therefore, $n=1500$

The margin of error is given as $\pm 3$%. Therefore, $E=0.03$.

The value of $\alpha$ is calculated as $\alpha$=1-Confidence Level

$\alpha=1-0.99=0.01$

Answer 2

Answer:

0.01  is alpha level

Step-by-step explanation:

Given that a survey of a magazine of 1500 adults revealed that 12% chose chocolate pie.

i.e. p = proportion of people who like chocolate pie = 0.12

Margin of error = ±0.03

The value of   q  =1-\hat p , =1-0.12 = 0.88

The sample size n  is given as 1500. Therefore,  n=1500

The confidence level is given as 99%

Hence alpha = 1- confidence level

=1-0.99=0.01

Hence answer is 0.01