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Inessa [10]
3 years ago
10

Round 12.034 to the nearest tenth

Mathematics
2 answers:
noname [10]3 years ago
6 0
12.034 rounded to the nearest tenth is 12.0
vovangra [49]3 years ago
5 0
The answer is 12.  Thanks (;
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What is the line of symmetry for the parabola whose equation is y = 3x2 + 24x - 1?
meriva
Hello :
<span>y = 3x2 + 24x - 1
   = 3(x²+8x) -1
   = 3 (x² +2(4)(x) +4²- 4² ) -1
   = 3((x+4)² -16)-1
y = 3(x+4)² - 49
</span><span>the line of symmetry is : x= - 4</span>
8 0
2 years ago
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1/3(-15 divide 1/2) 1/4 what does it equal
Dafna1 [17]

Answer:

-2.5 or - 2 1/2

Step-by-step explanation:

Writing out the expression Mathematically ;

1/3(-15÷1/2)1/4

Using PEMDAS :

Solving the bracket first

(-15 ÷ 1/2) = (-15 * 2/1) = - 30

We have :

1/3(-30)1/4 = - 10 * 1/4 = - 10 / 4 = - 2.5

-2.5 = - 2 1/2

3 0
2 years ago
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Softa [21]

Answer:

2

Step-by-step explanation:

6 0
2 years ago
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Write two equivalent expressions to represent the sum of the angles of this triangle.
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Answer:

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Step-by-step explanation:

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5 0
2 years ago
Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

6 0
3 years ago
Read 2 more answers
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