50+20=70
Have a great day:)
Answer:
Step-by-step explanation:
For a function f to have a maximum as per derivative rule we have to have
f'(x) =0, f"(x) <0
If second derivative =0 also then it is not maximum but point of inflections
Whenever f(x) = ax^n
we have
f'(x) = 0 gives x=0 and
f"(x) = n(n-1) ax ^(n-2)
So for n greater than or equal to there cannot be any maximum
And also for a straight line
y =-4x
y'=-4 and y"-0
No maximum
So only maximum can be for a funciton of the form y = ax^2
Here we do not have that all degrees are either 1 or greater than 1.
So no maximum for any funciton.
Answer:
chicken
Step-by-step explanation:
cuz im like that
4/7 for the 1st one., 8/9 for he 3rd dunno about middle one soz
Step-by-step explanation:
2*22/7*5=31.42857143
