Question

A battery with a potential difference of V connects to a resistor, and the resulting current is measured. You remove the battery, and a new battery with a potential difference of 2V is put in its place. As a result,a. the current will double.b. the resistance will double.c. both the current and the resistance will double.d. battery replacement will have no effect on the circuit.

Answer 1

Answer:

a. the current will doubled.

Explanation:

IN CASE 1:

Let , R be the resistance of resistor and it is given that the potential difference produced by battery is V.

Therefore, current through circuit is , $I=\dfrac{V}{R}.$

Now,

IN CASE 2:

The potential difference now is doubled i.e. 2 V.

Since, resistance of a body depends on its nature.

Therefore, Temperature remains constant.

So, current through circuit is , $I_2=\dfrac{2V}{R}=2\times I.$

Therefore, potion a) is correct.

Answer 2

Answer:

a. the current will double

Explanation:

I = Current

V = Voltage

R = Resistance

From Ohm's law we have the relation

$V=IR\\\Rightarrow I=\dfrac{V}{R}$

It can be seen that the current is proportional to the voltage.

This means that with increase in current there will be increase in voltage and vice versa.

So, if the voltage doubles the current will double