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storchak [24]
3 years ago
7

If light travels at 3 · 108 m/s and its frequency is 6 · 1015 Hz, then its wavelength is:

Physics
1 answer:
gladu [14]3 years ago
5 0

Answer:  5*10^-8 (B)

Explanation:  

-Given that the light is the speed

-We will be following the formula :

V= f (λ)

Where,  

V is the velocity  

F is the frequency  

λ is the wavelength  

3*10^8 = (6*10^15 )* λ

(3*10^8)/ (6*10^15 ) =  λ

5*10^-8m = λ answer

Note: λ is initially 0.5*10^-7 but to make it in the standard form it should be 5*10^-8. And do not forget to place the unit for the wavelength i.e. meter(m) otherwise you may lose marks!


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Answer:

The value is  u  =  3.23 *10^{7} \  m/s

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     Initial \  total  \  energy \ of the \  proton =  final \  total  \  energy \ of the \  proton

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    T_i  =  T_f

Here

   T_i  =  KE_i + PE_i

Here KE_i is the initial kinetic energy which is mathematically represented as

       KE_I  =  \frac{1}{2}  *  m * u ^2

Here  PE_i is the initial potential energy of the proton and the value is  0 J given that the proton is moving

Also  T_f is mathematically represented as

         T_f  =  KE_f + PE_f

Here  

        PE_f  is the final potential energy which is mathematically represented as

         PE_f  = \frac{k * Q_1 * Q_2}{r}

Here Q_1 is the charge on the proton with a value of Q_1 =  1.60 *10^{-19} \  C

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