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3 years ago

Can u help me please :)

Mathematics

1 answer:

GuDViN [60]3 years ago

7 0

She has to go down 4, back up to 0, and then up another 4, then back to 0.If positive 1 represents the first level above ground, negative numbers are a good choice to represent levels below ground. 8 flights; starting at -4 and moving to 4.

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Rewriting the left-hand side as follows,

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2 years ago

Write the equation of the parabola in vertex form. Vertex (2,3), point (1,-4)

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Step-by-step explanation:

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3 years ago

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9. Write the slope-intercept form of the equation of the line through the given points. Write answer as y=mx+b. through: (-4, 5)

densk [106]

Answer:

y = -x + 1

Step-by-step explanation:

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-5/5

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Now write in slope-intercept form:

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3 years ago

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Dvinal [7]

Answer:

the 3rd one

Step-by-step explanation:

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3 years ago

If N is the population of the colony and t is the time in days, express N as a function of t. Consider Upper N 0 is the origina

lesya [120]

Answer:

(a) $N(t)=Noe^{kt}$

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Step-by-step explanation:

(a)Given an original amount $N_o$ at t=0. The population of the colony with a growth rate $k \neq 0$ , where k is a constant is given as:

$N(t)=Noe^{kt}$

(b)If $N_o=1000$ and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

$1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)$

Therefore, our model is:

$N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t$

In 3 days time

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The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

$N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days$

In approximately 5 days, the population of mosquitoes will be 20,000.

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3 years ago

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