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Hunter-Best [27]
3 years ago
13

Can u help me please :)

Mathematics
1 answer:
GuDViN [60]3 years ago
7 0
She has to go down 4, back up to 0, and then up another 4, then back to 0.I<span>f positive 1 represents the first level above ground, negative numbers are a good choice to represent levels below ground. 8 flights; starting at -4 and moving to 4.</span>
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A wireless phone company charges a monthly fee of $39.99 plus $0.49 per minute for usage that exceeds the included minutes. Writ
Marizza181 [45]

Answer:

$54.20

Step-by-step explanation:

minute=m

total monthly cost = p

39.99 + .49m = p

39.99 + .49(29) =p

39.99 + 14.21 =p

54.2 =p

3 0
3 years ago
Each morning papa notes the birds feeding on his birdfeeder. so far this month he has seen 59 blue jays, 68 black crows, 12 red
Y_Kistochka [10]
The probability would be 59/140 or 42.14% (rounded: 42%).
7 0
3 years ago
Read 2 more answers
Jack crawled 3 ft and Christine crawled 3⁄4 the distance Jack crawled. If you add the distance they each crawled together, what
LUCKY_DIMON [66]
Christine crawled:
3 ft* (3/4)= 2.25 ft.

3 ft+ 2.25 ft= 5.25 ft

We already know that 1 ft= 12 in.

5.25 ft* (12in/ 1 ft)= 63 in.

The total distance the two children crawled together is 63 in~
5 0
3 years ago
Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437

P(sample average sediment density is at most 3.00)

P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

4 0
3 years ago
What do heating systems cooling systems and heat engines have in common
Lunna [17]

Answer:

is D

Step-by-step explanation:

for egny

5 0
3 years ago
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