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maria [59]
3 years ago
5

Which is a homogenous mixture?

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
8 0

Answer:

ceasar said is a homogeneous mixture

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When we looked at assigning the electrons in nitrogen to sites in the 2s and 2p orbitals, we used the 2s anti-bonding site. Whic
AveGali [126]

Answer:

B) Although this site is not desirable for making a bond between atoms, it is a good site in the sense that the electrons can be close to the nucleus.  

Explanation:

An antibonding orbital points away from the nuclei, with a node between them, so the electrons are not held close to the nuclei. The orbital is not desirable for bonding.

The diagram below shows a σ*1s molecular orbital, but a σ*2s orbital has a similar shape.

A) is true. The σ*1s orbital has the lowest energy.

C) is true. Any orbital can accommodate at most one electron pair.

D) is may be true. Orbital energy decreases as atomic number increases, so the orbital energy of an N₂ σ*2s molecule may be close to that of a sulfur atom's 2s orbital.

6 0
4 years ago
22 Which class of organic compounds contains nitrogen?(I) aldehyde(2) alcohol<br> (3) amine(4) ether
Marina CMI [18]
The answer is (3)amine. The aldehyde structure is -CHO. The alcohol structure is  -OH. The amine structure is -NH2. And the ether structure is R-O-R'. The "R" means other function groups.
7 0
3 years ago
Read 2 more answers
What is the volume of 0.410 moles of co2 at STP​
inna [77]

Answer: 9.18 Litres

Standard Temperature and Pressure (STP). Think of this as the perfect environment where the Temp. is 0°C or 273 Kelvin and Pressure is always 1 atm. This is only true in STP.

This question uses the Ideal Gas Equation:

PV=nRT

P= 1 atm

V = ??

T = 273 K (always convert to Kelvin unless told otherwise)

n = 0.410 mol

R = 0.0821 L.atm/mol.K

What R constant to use depends on the units of the other values. (look at the attachments) The units cancel out and only Litres is left. You simply multiply the values.

6 0
3 years ago
Read 2 more answers
Will the volume of a fixed amount of a gas increase, decrease, or remain unchanged with an increase in pressure at constant temp
Ghella [55]

Answer: The final volume decrease with an increase in pressure at constant temperature

Explanation:

According to Boyle's law, pressure of a gas is inversely proportional to the volume of a gas at constant temperature and constant number of moles.

{P_1V_1}={P_2V_2}

where,

P_1 = let initial pressure of gas = p

P_2 = final pressure of gas = 2p

V_1 = initial volume of gas = v

V_2 = final volume of gas = ?

Now put all the given values in the above equation, we get:

{p\times v}={2p\times V_2}

V_2=\frac{v}{2}

Thus the final volume decrease with an increase in pressure at constant temperature

5 0
3 years ago
The anticancer drug Platinol (cisplatin), Pt(NH3)2Cl2, reacts with the cancer cell's DNA and interferes with its growth. (a) Wha
USPshnik [31]

Answer:

(a) = 65.018% (b) = 1.807,83 grams

Explanation:

(a)

The mass % of platinum (pt) in platinol can be obtained applying the general percentage formula (portion of interest / total), in this case the platinol its composed of a single platinum (Pt) mole with molecular weight of 195.088 g/mol, two nitrogen (N)  mole of 28.012 g/mole each. six hydrogen (H) mole of 1.007 g/m and two chlorine (Cl) of 35.453 g/mole

N= 14.006 g/mole x 2 = 28.012

H= 1.0078 g/mole x 6 = 6.046

Cl= 35.453 g/mole x 2 = 70.906

Pt= 195. 088 g/mole x 1 = 195.088

the molecular weight of platinol its = 300.052g

% of Pt in platinol its = ((195.088 g/mole) /(300.052 g/mole))* 100= 65.018%

(b)

Assumption: 851/9 its in fact 851 $/gram

to know how many grams of Platinum can be bought it's necessary to divided the total money between the price of platinum, knowing how many grams can be bought and knowing the percentage of platinum in platinol, it's possible to know how many grams of platinol can be made from $1.00 million

grams of platinum $1'000.000/(851$/g) = 1.175,09 grams of Pt

grams of platinol =

1.175,09 grams of pt/ 0.65018 (grams of pt/grams of platinol)

grams of platinol = 1.807,83 grams of platinol

7 0
4 years ago
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