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a_sh-v [17]
3 years ago
10

Calculate delta g reaction at 298 k under the conditions 2hg+o2

Chemistry
1 answer:
Verizon [17]3 years ago
4 0

The balanced chemical reaction is 2Hg + O2 -> 2HgO. To calculate the delta G, we use the formula: ΔG = ΔH – TΔS. The ΔH is computed by subtracting the standard enthalpy of formation of the reactants from the products, multiplied correspondingly with their stoichiometric coefficients. The same is to obtain ΔS.

The necessary information all at 298 K are:

ΔH_Hg = 0 kJ/mol; since it is at its standard state

ΔS_Hg = 75.90 kJ/mol

ΔH_O2 = 0 kJ/mol; since it is at its standard state

ΔS_O2 = 0.161 kJ/mol K

ΔH_HgO = -90 kJ/mol

ΔS_HgO = 0.070 kJ/mol K

<span>Thus, the delta G of reaction is -132.022 kJ. The negative value denotes a spontaneous reaction. </span>

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Part A
Roman55 [17]

These are two questions and two answers

Question 1.

Answer:

  • <u>7.33 × 10 ⁻³ c</u>

Explanation:

<u>1) Data:</u>

a) m = 9.11 × 10⁻³¹ kg

b) λ =  3.31 × 10⁻¹⁰ m

c) c = 3.00 10⁸ m/s

d) s = ?

<u>2) Formula:</u>

The wavelength (λ), the speed (s), and the mass (m) of the particles are reltated by the Einstein-Planck's equation:

  • λ = h / (m.s)

  • h is Planck's constant: h= 6.626×10⁻³⁴J.s

<u>3) Solution:</u>

Solve for s:

  • s = h / (m.λ)

Substitute:

  • s = 6.626×10⁻³⁴J.s / ( 9.11 × 10⁻³¹ kg ×  3.31 × 10⁻¹⁰ m) = 2.20 × 10 ⁶ m/s

To express the speed relative to the speed of light, divide by c =  3.00 10⁸ m/s

  • s =  2.20 × 10 ⁶ m/s / 3.00 10⁸ m/s = 7.33 × 10 ⁻³

Answer: s = 7.33 × 10 ⁻³ c

Question 2.

Answer:

  • 2.06 × 10 ⁻³⁴ m.

Explanation:

<u>1) Data:</u>

a) m = 45.9 g (0.0459 kg)

b) s = 70.0 m/s

b) λ =  ?

<u>2) Formula:</u>

Macroscopic matter follows the same Einstein-Planck's equation, but the wavelength is so small that cannot be detected:

  • λ = h / (m.s)

  • h is Planck's constant: h= 6.626×10⁻³⁴J.s

<u>3) Solution:</u>

  • λ = h / (m.s)

Substitute:

  • λ =  6.626×10⁻³⁴J.s / ( 0.0459 kg ×  70.0 m/s) = 2.06 × 10 ⁻³⁴ m

As you see, that is tiny number and explains why the wave nature of the golf ball is undetectable.

Answer: 2.06 × 10 ⁻³⁴ m.  

5 0
3 years ago
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