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a_sh-v [17]
3 years ago
10

Calculate delta g reaction at 298 k under the conditions 2hg+o2

Chemistry
1 answer:
Verizon [17]3 years ago
4 0

The balanced chemical reaction is 2Hg + O2 -> 2HgO. To calculate the delta G, we use the formula: ΔG = ΔH – TΔS. The ΔH is computed by subtracting the standard enthalpy of formation of the reactants from the products, multiplied correspondingly with their stoichiometric coefficients. The same is to obtain ΔS.

The necessary information all at 298 K are:

ΔH_Hg = 0 kJ/mol; since it is at its standard state

ΔS_Hg = 75.90 kJ/mol

ΔH_O2 = 0 kJ/mol; since it is at its standard state

ΔS_O2 = 0.161 kJ/mol K

ΔH_HgO = -90 kJ/mol

ΔS_HgO = 0.070 kJ/mol K

<span>Thus, the delta G of reaction is -132.022 kJ. The negative value denotes a spontaneous reaction. </span>

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Which of the following is malleable?<br> A. glass <br> B. pottery <br> C. ice <br> D. gold
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Under which conditions (in terms of kinetic energy) does boiling occur? How is the kinetic energy in the liquid increased?
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            X(l) \rightleftharpoons X(g)

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3 years ago
What is the compound name for the formula [Ru(en)2Cl2]2+ and [Co(en)Cl2Br]-
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Answer:2C12

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3 0
3 years ago
The molarity of an aqueous sodium phosphate solution is 0.650 M. What is the molality of sodium ions present in this solution? T
netineya [11]

Answer:

molality of sodium ions is 1.473 m

Explanation:

Molarity is moles of solute per litre of solution

Molality is moles of solute per kg of solvent.

The volume of solution = 1 L

The mass of solution = volume X density = 1000mL X 1.43 = 1430 grams

The mass of solute = moles X molar mass of sodium phosphate = 0.65X164

mass of solute = 106.6 grams

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the molality = \frac{moles of solute}{mass of solvent in kg}=\frac{0.65}{1.323}= 0.491m

Thus molality of sodium phosphate is 0.491 m

Each sodium phosphate of molecule will give three sodium ions.

Thus molality of sodium ions = 3 X 0.491 = 1.473 m

7 0
3 years ago
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