2 ways to do this
a. find %Cl in CaCl2
2 x 35.45g/mole = 70.9g Cl
70.9g Cl / 110.9g/mole CaCl2 = 63.93% Cl in CaCl2
0.6963 x 145g = 92.7g = mass Cl
b. determine moles CaCl2 present then mass Cl
145g / 110.9g/mole = 1.31moles CaCl2 present
2moles Cl / 1mole CaCl2 x 1.31moles = 2.62moles Cl
2.62moles Cl x 35.45g/mole = 92.7g Cl
Oxygen has a strong double bond which has more stability than the single co-ordinate bond in ozone, therefore more energy is required to break the O2 bonding than ozone, so the ozone molecule is more reactive than oxygen gas. ... The oxygen free radical contains two unpaired electrons in its valence shell.
Answer:
Data:
mass of solute: 35g of NaCl
m.mass of solute: 58g/mol
volume of solution: 501mL
Molarity=?
Explanation:
501ml = 0.5dm3
M= g of solute/m.mass of solute*vol of solution
M= 35/58*0.5
M=1.20
Respiration . I’m pretty sure
I think the answer is producers
I hope that helped and have a nice day!! (: