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postnew [5]
3 years ago
8

E Of

Mathematics
1 answer:
RSB [31]3 years ago
3 0

Answer:

$3.40 for 20 rolls. B

Step-by-step explanation:

First, you should find the unit price. So, divide .51 by 3, which equals 0.17. So, it costs $.17 for one sandwich roll. Next, multiply that number by 20, to get $3.40. So, it costs $3.40 for 20 rolls

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An employee at a homemade wooden toy store earned $860 over the past week. The employee needs to pay 14% for Federal Income Tax
Sindrei [870]
Answer:
$713.8

Explanation:
14%of 860 = 120.4

3% of 860 = 25.8

so, subtract the sum of the above 2 values from 860.

860 - (120.4+25.8) = 860-146.2 = 713.8

Hope this helps

4 0
3 years ago
Read 2 more answers
Kia paid $10 for two charms. The price of each charm was a multiple of $2. What are the possible prices for the charms?
Fiesta28 [93]
Kia paid 20$ for each of her charms

7 0
4 years ago
Read 2 more answers
What percent of 28 is 21
ss7ja [257]
If we take 28 to be the 100%, what  is 21 off of it?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
28&100\\
21&p
\end{array}\implies \cfrac{28}{21}=\cfrac{100}{p}\implies p=\cfrac{21\cdot 100}{28}
5 0
4 years ago
Read 2 more answers
ASAP! GIVING BRAINLIEST! Please read question 10 THEN answer correctly! No guessing.
o-na [289]

Answer:

x=35

Step-by-step explanation:

62+2x+(x+13)=180

62+2x+x+13=180

3x+75=180

3x=180-75

3x=105

x=35

5 0
3 years ago
Who Washes? Erica and Aaron, who are siblings, have decided to use a lottery system to decide who will wash dishes every night.
Anestetic [448]

Given that Erica and AAron,are using lottery system to decide who will wash dishes every night.

They put some red and blue power chips and draw each one.  If same colour, Aaron will wash and if not same colours Erica will wash

If the game is to be fair, then both should have equal chances of opportunity for washing.

i.e. Probability for Erica washing = Prob of Aaron washing

i.e. P(different chips) = P(same colour chips)

Say there are m red colours and n blue colours.

Both are drawing at the same time.

Hence Prob (getting same colour) = (mC2+nC2)/(m+n)C2

Probfor different colour = mC1+nC1/(m+n)C2

The two would be equal is mC2 +nC2 = m+n

This is possible if mC2 =m and nC2 = n.

Or m = 2+1 =3 and n =3

That for a fair game we must have both colours to be 3.


3 0
3 years ago
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