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coldgirl [10]
4 years ago
14

Express the following numbers as decimals: (a) 1.52 x 10^-2, (b) 7.78 x 10^-8, (c) 1 x 10^-6, (d) 1.6001 x 10^3.

Chemistry
1 answer:
Alchen [17]4 years ago
5 0

Answer :

(a) 0.0152

(b) 0.0000000778

(c) 0.000001

(d) 1600.1

Explanation :

Scientific notation : It is the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example :

5000 is written as 5.0\times 10^3

889.9 is written as 8.899\times 10^{-2}

In this examples, 5000 and 889.9 are written in the standard notation and 5.0\times 10^3  and 8.899\times 10^{-2}  are written in the scientific notation.

(a) 1.52\times 10^{-2}

The standard notation is, 0.0152

(b) 7.78\times 10^{-8}

The standard notation is, 0.0000000778

(c) 1\times 10^{-6}

The standard notation is, 0.000001

(d) 1.6001\times 10^{3}

The standard notation is, 1600.1

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yes but it depends

Explanation:

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balu736 [363]

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Explanation:

This problem deals with balancing of chemical equations.

   Every chemical equations obey the law of conservation of matter which states that "in chemical reactions, matter is usually conserved and are not produced, they are simply recombined".

  Equation of reaction:

      BaO₂   +   H₂SO₄  ⇒  H₂O₂  +  BaSO₄

Let us use a mathematical approach to balance this equation by setting up simple algebraic equations:

        aBaO₂   +   bH₂SO₄  ⇒  cH₂O₂  +  dBaSO₄

a, b, c and d are the number of moles that will balance the equation;

 Conserving Ba:   a = d

                       O:   2a + 4b = 2c + 4d

                        H:    2b = 2c

                         S:    b  = d

now let a = 1

              d = 1

               b = 1

                c  = 1

we see that the equation is already balanced

learn more:

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3 0
3 years ago
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write the ground-state electron configurations of the seventh and eighth elements in the first transition series in Universe fif
Tju [1.3M]

Answer: Check explanation.

Explanation:

Transition metals are metallic elements that can be found in the Groups IVB–VIII, IB, and IIB on the periodic chart.

The question require us to write down the GROUND state electronic configuration of the first fifth transition metal, sixth transition metal, seventh transition metal element and the eighth transition metal.

NOTE: we are Starting from Argon, which has 18 electrons.

The fifth transition metal is Manganese,Mn. Manganese has 25 electrons, that is, 25- 18= 7. Therefore, it needs seven electrons to complete the configuration.

Hence, The ground state electronic configuration = [Ar)] 3d5. 4s2.

The first sixth Transition metal is iron,Fe. Iron has 26 electrons, that is, 26 - 18 = 8. Therefore, it need eight Electrons to complete the ground state electronic configuration.

Hence, the ground state electronic configuration of Fe= [Ar] 3d6. 4s2.

The first seventh transition metal is Cobalt, Co. It has 27 Electrons, therefore, 27- 18 = 9. Therefore, it needs 9 Electrons to complete its ground state electronic configuration.

Ground state electronic configuration of Co= [Ar] 3d7. 4s2.

The first eight Transition metal is Nickel. It has 28 electrons. Therefore, 28-18= 10. So, it needs 10 Electrons to complete its ground state electronic configuration.

Hence, the Ground state electronic configuration of Ni= [Ar] 3d8. 4s2.

5 0
3 years ago
Urgent 25 points!!
LekaFEV [45]

Answer:

A. Yes, Amanda find the number of moles of NaCl correctly.

B. 0.73 M.

Explanation:

<em>A. Did Amanda find the number of moles of NaCl correctly? If not, explain. </em>

  • Yes, Amanda find the number of moles of NaCl correctly.
  • The relation to find the no. of moles of NaCl is:

<em>No. of moles (n) of NaCl = mass/molar mass.</em>

mass of NaCl = 32.0 g, molar mass of NaCl = 58.45 g/mol.

∴ No. of moles (n) of NaCl = mass/molar mass = (32.0 g)/(58.45 g/mol) = (32.0 g NaCl)*(1 mol of NaCl)/(58.45 g NaCl) = 0.547 mol ≅ 0.55 mol.

<em>B. What does Amanda need to do next to calculate the molarity of the NaCl solution? Show your work for full credit.</em>

<em></em>

  • Molarity is the no. of moles of solute dissolved in a 1.0 liter of a solution.

∴ M = (no. of moles of NaCl)/(volume of solution (L)) = (0.55 mol)/(0.75 L) = 0.73 M.

5 0
4 years ago
How many grams of NaF form when .5 mol of HF reacts with excess Na2SiO3?
IgorLugansk [536]

Answer:

5.25g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is shown below:

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From the balanced equation above,

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Mass of NaF =..?

Mass = mole x molar mass

Mass of NaF = 0.125 x 42

Mass of NaF = 5.25g

Therefore, 5.25g of NaF is produced from the reaction.

7 0
3 years ago
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