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defon
3 years ago
9

Describe the De Borglie's hypothesis​

Chemistry
1 answer:
Advocard [28]3 years ago
3 0

Answer:

The De Broglie hypothesis proposes that all matter exhibits wave-like properties and relates the observed wavelength of matter to its momentum. After Albert Einstein's photon theory became accepted, the question became whether this was true only for light or whether material objects also exhibited wave-like behavior.

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Answer:

For density you divide the mass by cm so for trail one the answer would be  34.31/1.64=20.9

Explanation:

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4 years ago
Bronsted lowry base that are not considered Arrhenius bases
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Answer: An example is <u>sodium ethoxide (NaOCH2CH3) dissolved in ethanol (CH3CH2OH).</u>

Hope this helps!

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2 years ago
Which components of a galaxy move in circular patterns or revolve around a star?
Sholpan [36]

Answer:

C.

Explanation:

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5 0
2 years ago
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How many grams of calcium chloride would you need to make 1 L of solution containing 5 ppm calcium (Ca)?
Tresset [83]

Explanation:

The given data is as follows.

           Volume = 1 L,    Concentration of Ca = 5 ppm or 5 mg/L

As 1 mg = 0.001 g so, 5 mg /L will be equal to 0.005 g/l. Molar mass of calcium is 40.078 g/mol.

Hence, calculate molarity of calcium as follows.

           Molarity of Ca = \frac{\text{given concentration}}{\text{molar mass}}

                                  = \frac{0.005 g/l}{40.078 g/mol}

         Molarity of Ca = 1.25 \times 10^{-4} M

Hence, molarity of CaCl_{2} is 1.25 \times 10^{-4} M. Since, volume is same so, moles of calcium chloride will be 1.25 \times 10^{-4} mol.

Thus, we can conclude that mass of CaCl_{2} will be as follows.

             1.25 \times 10^{-4} \times 110.984       (molar mass of CaCl_{2} = 110.984 g/mol)

               = 0.0138 g

Thus, we can conclude that mass of CaCl_{2} is 0.0138 g.

4 0
3 years ago
Water supplies are often treated with chlorine as one of the processing steps in treating wastewater. Estimate the liquid diffus
jekas [21]

Answer:

⇒D_AB= 1.21×10^(-9)

Explanation:

Wike chang  equation is given as:

D_{AB}= \frac{117.3\times10^{-18}\times\(\phi\times M_B)^{0.5}\times T}{\mu\times\nu^{0.6}}

Where

D_AB= diffusivity of chlorine in water

Φ= 2.26 for water as solvent

ν= 0.0484 for chlorine as solute

M_B = Molecular weight of water

τ= temperature=289 K

μ= viscosity = 1.1×10^{-3}

Now putting these values in the above equation we get

D_{AB}= \frac{117.3\times10^{-18}\times\(\2.26\times18)^{0.5}\times289}{\1.1\times10^{-3}\times\0.0484^{0.6}}

⇒D_AB= 1.21×10^(-9)

7 0
3 years ago
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