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nasty-shy [4]
3 years ago
10

Jill is studying the temperature output of an ammonium chloride hand warmer with a calorimeter. What change should she expect to

see in the temperature of the water over time?
A) The water will continue to heat up as the experiment progresses.

B) The water will remain a relatively constant temperature during the experiment.

C) The water will gradually cool off throughout the experiment like the hand warmer.

D) Initially the water will heat up and then it will slowly cool off as the hand warmer does.
Chemistry
1 answer:
ANEK [815]3 years ago
7 0

Answer:

The water will continue to heat up as the experiment progresses.

Explanation:

When a person's fingers are cold or has a muscles ache, one can use chemical hand warmers to heat them up. There are two types of chemical hand warmer products, and they all depend on exothermic chemical reactions to work.

However, ammonium chloride dissolution is endothermic but its crystalization is exothermic. When used as a hand warner with a calorimeter, it is found that the temperature of the water increases steadily due to the crystalization of the ammonium chloride. Hence the answer.

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Explanation:

Reproductive isolation mechanism is of two types:

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A volume of 90.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2
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Explanation:

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n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=2\\M_1=1.50 M\\V_1=24.7 mL\\n_2=1\\M_2=?\\V_2=90.0 mL

Putting values in above equation, we get:

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0.823 M was the molarity of the KOH solution.

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