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nasty-shy [4]
3 years ago
10

Jill is studying the temperature output of an ammonium chloride hand warmer with a calorimeter. What change should she expect to

see in the temperature of the water over time?
A) The water will continue to heat up as the experiment progresses.

B) The water will remain a relatively constant temperature during the experiment.

C) The water will gradually cool off throughout the experiment like the hand warmer.

D) Initially the water will heat up and then it will slowly cool off as the hand warmer does.
Chemistry
1 answer:
ANEK [815]3 years ago
7 0

Answer:

The water will continue to heat up as the experiment progresses.

Explanation:

When a person's fingers are cold or has a muscles ache, one can use chemical hand warmers to heat them up. There are two types of chemical hand warmer products, and they all depend on exothermic chemical reactions to work.

However, ammonium chloride dissolution is endothermic but its crystalization is exothermic. When used as a hand warner with a calorimeter, it is found that the temperature of the water increases steadily due to the crystalization of the ammonium chloride. Hence the answer.

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The density of a gold nugget is 19.3 g/cm3. If the volume of the gold nugget is 0.00369 L the mass of the nugget is
Sauron [17]

Answer:

The answer to your question is 71.22 g

Explanation:

Data

Density = 19.3 g/cm³

Volume = 0.00369

mass = ?

Formula

Density = \frac{mass}{volume}

Solve for mass

mass = density x volume

Process

1.- Convert volume from liters to cubic centimeters

                 1 l ----------------  1000 cm³

             0.00369l ---------   x

                x = (0.00369 x 1000 ) / 1

                x = 3.69 cm³

2.- Substitution

       mass = 19.3 x 3.69

3.- Simplification and result

       mass = 71.22 g

6 0
3 years ago
((2.0265-2.02)/2.0265) x 100.00
lianna [129]

Answer 0.5

when reporting calculations from sig figs, report the number of sig figs in the least accurate measurement

so

((2.0265-2.02)/2.0265) x 100.00

((2.0265/2.0265) - (2.02/2.03)) X 100.00

(1.0000 -0.995) X 100.00

0.005 X 100.00

0.5

3 0
3 years ago
(A) 2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(l) (B) C2H3O2-(aq) + H3O+(aq) → HC2H3O2(aq) + H2O(l) (C) 4 H+(aq) + 4 Co2+(aq) + O2
Anestetic [448]

Answer:

The reaction (E) 2 H₂O₂ (l) → O₂ g) + 2 H₂O (l) has a single species that is both oxidized and reduced.

Explanation:

Given the reaction (E):

2 H₂O₂ (l) → O₂ g) + 2 H₂O (l)

In hydrogen peroxide, oxygen has an oxidation state of -1. We can see that the reaction is balanced.

The products of the reaction are:

O₂ (the oxidation state of the Oxygen is 0)

H₂O (the oxidation state of the Oxygen is -2)

Hence, 1 mol of Oxygen changes its oxidation state from -1 to 0 (oxidation) and 1 mol of Oxygen changes its oxidation state from -1 to -2 (reduction).

The reaction (E) has a single species that is both oxidized and reduced.

6 0
3 years ago
How do you find the mass of original KClO3 sample
emmasim [6.3K]
You cannot find it if you do not know the information.  Was there a molar mass given or do you know if it is asking for the molar mass?
5 0
3 years ago
No tengo pregunta jajaja
masha68 [24]

Answer:

--

------Explanation:

8 0
3 years ago
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