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RoseWind [281]
3 years ago
13

The adjustments that your eyes make as they look from objects near to objects far away or from objects far away to objects close

r can serve as cues to depth in and of themselves. This source of information about depth is known as______.
Physics
1 answer:
Hatshy [7]3 years ago
6 0

Answer:

Oculomotor depth cues is based on two things convergence and accommodation,for the eyes to see near by things within 25cm near point we look inwards at this point the muscles holding the lens tighten up to see near by things unlike when we see far things we tend to look outwards with our eye muscles relaxing.

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What is the distance of separation between objects of masses 5.6 x 10 5 kg and 8.8 x 10 6 kg if the force of gravity between the
AlladinOne [14]

Answer:

2.87m

Explanation:

Using the law of gravitation to solve this question

F = GMm/r²

G is the gravitational constant

M and m are the masses

r is the distance between the masses

Substitute the given values

G = 6.67×10^-11 m³/kgs²

M =8.8 x 10^6 kg

m = 5.6 x 10^5 kg

F =440N

400 = 6.67×10^-11×8.8 x 10^6 ×5.6 x 10^5/r²

400r² = 328.698×10

400r² = 3286.98

r² = 3286.98/400

r² = 8.21745

r = √8.21745

r = 2.87m

Hence the distance of separation is 2.87m

7 0
3 years ago
What stands for sound navigation and ranging
anastassius [24]
Sonar, originally an <span>acronym for SOund Navigation And Ranging
</span>a technique that uses sound<span> propagation.</span>
6 0
3 years ago
Suppose you drive an average of 25 miles a day, for a total of 60 years in a lifetime. The total distance you would have covered
Ahat [919]

The total distance you would have covered is equivalent to going around the earth 22 times.

<h3>Total distance traveled</h3>

The total distance traveled at a given speed and time of motion is calculated as follows;

Distance = speed x time

Distance = \frac{25 \ miles}{day} \times \frac{365 \ days}{1 \ year} \times 60 \ years\\\\Distance = 547, 500 \ miles

<h3>Distance round the Earth</h3>

The distance round the earth or circumference of the earth of the earth has been given as 25,000 miles

<h3>Number of times round the earth</h3>

n = \frac{547,500}{25,000} \\\\ n = 21.9 \ times \ \approx 22 \ times

Thus, the total distance you would have covered is equivalent to going around the earth 22 times.

Learn more about distance here: brainly.com/question/17273444

3 0
2 years ago
Ree is 27 inches tall on her first birthday. She grows around 6 inches per year after that. What is the rate of change for the s
RSB [31]

Answer:

6

Explanation:

The rate of change in this scenario corresponds to the number of inches that Ree grows every year. Basically, Ree's height can be written as a linear equation as follows:

y=mx+q

where

x is the number of years after the first birthday

y is the height in inches

q = 27 is the height of Ree on her first birthday

m = 6 is the inches gained by Ree at each birthday

So the equation can also be rewritten as

y = 6x + 27

4 0
3 years ago
Read 2 more answers
I don’t get this helpp
Annette [7]

Answer & Explanation:

Formula

Acceleration = change in velocity / time taken

Acceleration = 5 / 300

Acceleration = 0.016

hence final answer = 0 m / s^2

3 0
2 years ago
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