Step-by-step explanation:
Simple interest formula

Compound interest formula

a.

Simple interest is $125
b
. 
Compound interest is $125
c. the result for both a and b are the same
d.

the simple interest is $375
e
. ![A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385](https://tex.z-dn.net/?f=A%20%3D%205000%20%281%20%2B%20%5Cfrac%7B0.025%7D%7B1%7D%29%5E%7B1%2A3%7D%5D%20%5C%5CA%3D5000%281.025%29%5E3%20%5C%5CA%3D5000%281.077%29%5C%5CA%3D%205385)
the compound interest is $385
f. the result compared, compound interest is $10 more than simple interest
g.

the simple interest is $600
h.
![A = 5000 (1 + \frac{0.02}{1})^{1*6}] \\A=5000(1.12)^6 \\A=5000(1.9738) \\A= 9869](https://tex.z-dn.net/?f=A%20%3D%205000%20%281%20%2B%20%5Cfrac%7B0.02%7D%7B1%7D%29%5E%7B1%2A6%7D%5D%20%5C%5CA%3D5000%281.12%29%5E6%20%5C%5CA%3D5000%281.9738%29%20%5C%5CA%3D%209869)
the compound interest is $4869
i. the result from g and h, h is over 8 times bigger than g.
j. interest compound annually is not the same as simple interest, only for the case of a and b seeing that it is for 1 year. but for 2years and above there is difference as seen in c to h
Answer:
approximately 27 grams
Work Shown:
Half life formula
y = A*(0.5)^(x/H)
where,
A = starting amount = 30 grams
H = half life period = 90 years
x = number of years that pass by = 12
y = amount left over after x years
Let's plug the values for x, A and H into the formula to find y
y = A*(0.5)^(x/H)
y = 30*(0.5)^(12/90)
y = 27.3516746567466
y = 27 .... rounding to the nearest whole number
Answer: 7
Step-by-step explanation: