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Mumz [18]
4 years ago
8

Identify the molecules or ions below as Lewis acids, Lewis bases, or neither. If there is more than one possible site in the mol

ecule/ion, focus on the central or the charged atom. H3C-CH2-CH3 __________
Chemistry
1 answer:
oksano4ka [1.4K]4 years ago
8 0

Answer: Neither

Explanation:

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

CH_3CH_2CH_3 is a hydrocarbon containing carbon and hydrogen, which have almost same electronegativity values. Thus is a non polar molecule.

It does not donate electrons as it does not contain any lone pair of electrons. It can not accept electrons as it's octet is already complete. Thus is neither a lewis acid nor a lewis base.

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How are physical and chemical changes different
Wittaler [7]

Answer:

physic

Explanation:

physical chnages are chnages to the appearance

chemical chnages are chnages like

color temperature chnaging fromna gas to a liquid etc

3 0
4 years ago
Read 2 more answers
Nitroglycerin is a dangerous powerful explosive that violently decomposes when it is shaken or dropped. The Swedish chemist Alfr
Ganezh [65]

Answer:

a. 4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)

b. 146.0 g

Explanation:

Question 1 (a). Just as the problem states, liquid nitroglycerin decomposes into nitrogen gas N_2, oxygen gas O_2, water vapor H_2O and carbon dioxide CO_2. Let's write the decomposition of nitroglycerin into these 4 components:

C_3H_5N_3O_9 (l)\rightarrow N_2 (g) + O_2 (g) + H_2O (g) + CO_2 (g)

Now we need to balance the equation. Firstly, notice we have 3 carbon atoms on the left and 1 on the right, so let's multiply carbon dioxide by 3:

C_3H_5N_3O_9 (l)\rightarrow N_2 (g) + O_2 (g) + H_2O (g) + 3 CO_2 (g)

Now, we have 3 nitrogen atoms on the left and 2 on the right, so let's multiply nitrogen on the right by \frac{3}{2}:

C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + O_2 (g) + H_2O (g) + 3 CO_2 (g)

We have 5 hydrogen atoms on the left, 2 on the right, so let's multiply the right-hand side by \frac{5}{2}:

C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + O_2 (g) + \frac{5}{2} H_2O (g) + 3 CO_2 (g)

Finally, count the oxygen atoms. We have a total of 9 on the left. On the right we have (excluding oxygen molecule):

\frac{5}{2} + 6 = 8.5

This leaves 9 - 8.5 = 0.5 = \frac{1}{2} of oxygen. Since oxygen is diatomic, we need to take one fourth of it to get one half in total:

C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + \frac{1}{4} O_2 (g) + \frac{5}{2} H_2O (g) + 3 CO_2 (g)

To make it look neater without fractional coefficients, multiply both sides by 4:

4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)

Question 2 (b). Now we can make use of the balanced chemical equation and apply it for the context of this separate problem. We're given the following variables:

V_{CO_2} = 41.0 L

T = -14.0^oC + 273.15 K = 259.15 K

p = 1 atm

Firstly, we may find moles of carbon dioxide produced using the ideal gas law pV = nRT.

Rearranging for moles, that is, dividing both sides by RT (here R is the ideal gas law constant):

n_{CO_2} = \frac{pV_{CO_2}}{RT} = \frac{1 atm\cdot 41.0 L}{0.08206 \frac{L atm}{mol K}\cdot 259.15 K} = 1.928 mol

According to the stoichiometry of the balanced chemical equation:

4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)

4 moles of nitroglycerin (ng) produce 12 moles of carbon dioxide. From here we can find moles o nitroglycerin knowing that:

\frac{n_{ng}}{4} = \frac{n_{CO_2}}{12} \therefore n_{ng} = \frac{4}{12}n_{CO_2} = \frac{1}{3}\cdot 1.928 mol = 0.6427 mol

Multiplying the number of moles of nitroglycerin by its molar mass will yield the mass of nitroglycerin decomposed:

m_{ng} = n_{ng}\cdot M_{ng} = 0.6427 mol\cdot 227.09 g/mol = 146.0 g

3 0
3 years ago
When light is shown on a mixture of chlorine and chloromethane, carbon tetrachloride is one of the components of the final react
velikii [3]

A free-radical substitution reaction is likely to be responsible for the observations. The reaction mechanism of a reaction like this can be grouped into three phases:

  • Initiation; the "light" on the mixture deliver sufficient amount of energy such that the halogen molecules undergo homologous fission. It typically takes ultraviolet radiation to initiate fissions of the bonds.  
  • Propagation; free radicals react with molecules to produce new free radicals and molecules.
  • Termination; two free radicals combine and form covalent bonds to produce stable molecules. Note that it is possible for two carbon-containing free-radicals to combine, leading to the production of trace amounts of long carbon chains in the product.

Initiation

\text{Cl}-\text{Cl} \stackrel{\text{UV}}{\to} \text{Cl}\bullet + \bullet\text{Cl}

where the big black dot indicates unpaired electrons attached to the atom.

Propagation

\text{CH}_3\text{Cl}+ \text{Cl}\bullet \to \bullet\text{CH}_2\text{Cl} + \text{HCl}

\bullet\text{CH}_2\text{Cl} + \text{Cl}_2 \to \text{CH}_2\text{Cl}_2 + \text{Cl}\bullet

\text{CH}_2\text{Cl}_2 + \text{Cl}\bullet \to \bullet\text{CHCl}_2 + \text{HCl}

\bullet\text{CHCl}_2+ \text{Cl}_2 \to \text{CHCl}_3 + \bullet \text{Cl}

\text{CHCl}_3 + \text{Cl}\bullet \to \bullet\text{CCl}_3 + \text{HCl}

\bullet\text{CCl}_3 + \text{Cl}_2 \to \text{CCl}_4 + \text{Cl}\bullet

Termination

\text{Cl}\bullet + \bullet\text{Cl} \to \text{Cl}-\text{Cl}

8 0
3 years ago
PLEASE PLEASE PLEASE ANSWER THIS CORRECTLY ASAP 50 POINTS
tresset_1 [31]

If I remember correctly, it would be B. A very large amount of energy is produced from a tremendous mass.

4 0
4 years ago
What causes an ice cube to melt when removed from a freezer?
OverLord2011 [107]

Answer:

the melting process begins right away because the air temperature around the ice cubes is warmer than the temperature in the freezer

4 0
3 years ago
Read 2 more answers
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