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3 years ago

Balance the following chemical equation: C2H60+02 → CO2 + H2O

Chemistry

1 answer:

lilavasa [31]3 years ago

8 0

Answer: C2h6O + 3O2 → 2CO2 + 3H2O

Explanation:

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In the periodic table, a set of properties repeats from

jok3333 [9.3K]

in the periodic table, a set of properties repeats from row to row

3 0

3 years ago

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From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp

Nina [5.8K]

<u>Answer:</u> The concentration of $NH_3$ required will be 0.285 M.

<u>Explanation:</u>

To calculate the molarity of $NiC_2O_4$ , we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of $NiC_2O_4$ = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M$

For the given chemical equations:

$NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}$

$Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9$

Net equation: $NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?$

To calculate the equilibrium constant, K for above equation, we get:

$K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48$

The expression for equilibrium constant of above equation is:

$K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}$

As, $NiC_2O_4$ is a solid, so its activity is taken as 1 and so for $C_2O_4^{2-}$

We are given:

$[[Ni(NH_3)_6]^{2+}]=0.016M$

Putting values in above equations, we get:

$0.48=\frac{0.016}{[NH_3]^6}}$

$[NH_3]=0.285M$

Hence, the concentration of $NH_3$ required will be 0.285 M.

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3 years ago

What is the salt produced when calcium hydroxide, Ca(OH)2, reacts with phosphoric acid, H3PO4, in a neutralization reaction?

Pavel [41]

$3Ca(OH) _{2} +2H _{3} PO _{4}$ ⇒ $6H _{2} O+Ca _{3}(PO _{4}) _{2}$
Calcium phosphate. Which is your Ca3(PO4)2.

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2 years ago

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Round 647.155 to nearest hundredt

lisov135 [29]

Answer:600

Explanation:

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2 years ago

A 120.5 g sample of water loses -7525 J of energy. What was the

dusya [7]

Answer:14.93

Explanation:heat gained=heat lost

120.5 ×4.184×change=7525

7525÷504.172

Ans14.925

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3 years ago