Answer:
EQUILATERAL TRIANGLE = 3/27
<h2>SO THE ANS IS 9 .</h2>
I HOPE IT IS HELPFUL
What is the answer please tell me!
1 answer:
You might be interested in
<h3>1. Inscribe a circle ΔJKL. Identify the point of concurrency that is the center of the circle you drew. </h3>
<h3>2. Circumscribe a circle ΔFGH. Identify the point of concurrency that is the center of the circle you drew. </h3>
To inscribe a circle in the attached triangle, we must follow the following steps. The resultant figure is the first one below.
1. Draw the angle bisector of angle JKL. The straight line in the green one.
2. Draw the angle bisector of angle KLJ. The straight line in the blue one.
3. Draw point D at these two lines.
4. Draw a line through point D perpendicular to side JK. The straight line in the red one.
5. Mark point G at the red line and side JK.
6. Draw a circle with center at D (point of concurrency) and a radius of DG.
<h3>2. Circumscribe a circle ΔFGH. Identify the point of concurrency that is the center of the circle you drew. </h3>
To circumscribe a circle in the attached triangle, we must follow the following steps:
1. Draw the perpendicular bisector of the side FG. The straight line in the red one. The resultant figure is the second one below.
2. Draw the perpendicular bisector of the side GH. The straight line in the blue one.
3. The center of the circle is the intersection of these two lines
4. Draw a circle with center at D (point of concurrency).
<h3>3. Construct the two lines tangents to circle</h3>A tangent to a circle is a straight line that touches the circle at an only point. If a point A is outside a circle, we can draw two lines that pass through this point and are tangent to the circle at two different points each. So this is shown in the third figure. Lines red and blue are tangent to the circle at two different points.
Answer:
Please see attached graph.
Step-by-step explanation:
The equations for straight lines are given as:
i) y = x +4
ii) y= x-4
Yon can form a table for values of x and y that are true for an equation and use these values as coordinates ( x,y ) to plot the graphs and view the lines to select the correct labels for the equations.
For i)
y= x+4
x y coordinates
-3 1 (-3,1 )
-2 2 (-2,2)
-1 3 (-1,3)
0 4 ( 0,4)
1 5 ( 1,5)
2 6 ( 2,6)
3 7 ( 3,7)
Plot the points on a graph tool and draw the line. Do the same for the second equation to view both graphs as shown in the attached graph.
