Because we should convert units within the metric system
Ur answer is 3 and i'm sure of it
Answer:
The work required to pump the liquid out of the spout is 2.6 × 10⁶ J
Explanation:
<u>Step 1:</u> consider a spherical tank, sliced into two equal part, since it is half filled.
The new circular surface has a radius, if we construct a right angled-triangle on the surface. The initial radius of the spherical tank becomes the hypotenuse of the triangle and the radius is calculated as follows;
volume (v)
<u>Step 2:</u> Total height, d, in which the liquid is pumped out;
d = b + 3 + 1
= b + 4
<u>Step 3:</u> Force required to pump the liquid out:
F = mg
But, m = density (ρ) x volume (v)
F = ρvg
Given;
ρ = 900 kg/m³ and g = 9.8 m/s²
<u>Step 4:</u> The work done in pumping the liquid out of the spout
W = F x d
Therefore, the work required to pump the liquid out of the spout is 2.6 × 10⁶ J
Answer:
The answer is Temperature.