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choli [55]
1 year ago
10

a piston-cylinder apparatus has a 4 kg piston with a diameter of 5 cm resting on a body of water 60 cm high. atmospheric pressur

e is 101 kpa, and the temperature of the water is 250˚c. what is the mass of water in the container?
Physics
1 answer:
Leokris [45]1 year ago
8 0

The mass of the water in the container is 10,104.00 kg.

A schematic diagram of a piston-cylinder apparatus is shown in the adjoining image.

In the above case, the atmospheric pressure applied by the piston and the weight of the piston should balance the weight of the water inside the container

Hence,

Atmospheric Pressure x Area of Piston + Mass of piston x g = Mass of water x g

101 x 10^3 x pi x (2.5 x 10^-2)^2 + 4 x 10 = Mass of water x 10

Mass of water x 10 = 101,040.001

Mass of Water = 101,040.001/10

Mass of Water = 10,104 kg

Hence, the mass of the water in the container is 10,104.00 kg.

To know more about the "piston-cylinder apparatus", refer to the link given below:

brainly.com/question/13999257?referrer=searchResults

#SPJ4

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A ferry coming into port is sailing at 12 m/s. It takes 2.5km to come to rest in the port. Calculate the deceleration of the fer
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Answer:    -0.0288 m/s^2

Explanation:

Let's suppose that the ferry decelerates at a constant rate A (deceleration is an acceleration in the opposite direction to the original motion of an object)

Then the acceleration equation of the ferry will be:

a(t) = -A

(the negative sign is because this acceleration is in the opposite direction with respect to the movement of the ferry)

To get the velocity equation of the ferry, we need to integrate with respect to the time, t, we will get:

v(t) = -A*t + v0

where v0 is the initial velocity of the ferry, v0 = 12m/s.

v(t) = -A*t + 12m/s

For the position equation of the ferry we need to integrate again over time:

p(t) = (-A/2)*t^2 + (12m/s)*t + p0

Where p0 is the initial position of the ferry, in this case, it can be zero, because it will depend on where we put the origin on our coordinate axis.

then p0 = 0m

P(t) = (-A/2)*t^2 + (12m/s)*t

The ferry will come to rest at the moment when it's velocity is equal to zero, this will happen when:

v(t) = 0m/s = -A*t + 12m/s

We need to find the value of t.

A*t = 12m/s

t = (12m/s)/A

Now we can replace this in the position equation because we know that the ferry needs 2.5 km or 2500 meters to come to rest.

p(  (12m/s)/A) = 2500m =  (-A/2)*( (12m/s)/A)^2 + (12m/s)*((12m/s)/A)

2500m = (-72 m^2/s^2)/A + (144m^2/s^2)/A

2500m = (72 m^2/s^2)/A

2500m*A = (72 m^2/s^2)

A = (72 m^2/s^2)/2500m = 0.0288 m/s^2

and the acceleration of the ferry was -A, then the acceleration of the ferry is:

-0.0288 m/s^2

4 0
3 years ago
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