a piston-cylinder apparatus has a 4 kg piston with a diameter of 5 cm resting on a body of water 60 cm high. atmospheric pressur
1 answer:
The mass of the water in the container is 10,104.00 kg.
A schematic diagram of a piston-cylinder apparatus is shown in the adjoining image.
In the above case, the atmospheric pressure applied by the piston and the weight of the piston should balance the weight of the water inside the container
Hence,
Atmospheric Pressure x Area of Piston + Mass of piston x g = Mass of water x g
101 x 10^3 x pi x (2.5 x 10^-2)^2 + 4 x 10 = Mass of water x 10
Mass of water x 10 = 101,040.001
Mass of Water = 101,040.001/10
Mass of Water = 10,104 kg
Hence, the mass of the water in the container is 10,104.00 kg.
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Answer:
U² = 142.86 N
U¹ = 357.14 N
Explanation:
Taking summation of the moment about point A, we get the following equilibrium equation: (taking clockwise direction as positive)
where,
W = weight of boy = 500 N
U² = reaction ay B = ?
Therefore,
<u>U² = 142.86 N</u>
Now, taking summation of forces on the plank. Taking upward direction as positive, for equilibrium position:
<u>U¹ = 357.14 N</u>