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choli [55]
1 year ago
10

a piston-cylinder apparatus has a 4 kg piston with a diameter of 5 cm resting on a body of water 60 cm high. atmospheric pressur

e is 101 kpa, and the temperature of the water is 250˚c. what is the mass of water in the container?
Physics
1 answer:
Leokris [45]1 year ago
8 0

The mass of the water in the container is 10,104.00 kg.

A schematic diagram of a piston-cylinder apparatus is shown in the adjoining image.

In the above case, the atmospheric pressure applied by the piston and the weight of the piston should balance the weight of the water inside the container

Hence,

Atmospheric Pressure x Area of Piston + Mass of piston x g = Mass of water x g

101 x 10^3 x pi x (2.5 x 10^-2)^2 + 4 x 10 = Mass of water x 10

Mass of water x 10 = 101,040.001

Mass of Water = 101,040.001/10

Mass of Water = 10,104 kg

Hence, the mass of the water in the container is 10,104.00 kg.

To know more about the "piston-cylinder apparatus", refer to the link given below:

brainly.com/question/13999257?referrer=searchResults

#SPJ4

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Explanation:

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Wave 1 has a wave function:

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Wave 2 has a wave function:

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π is in radians.

When Superposition occurs, the new wave is represented by:

y(x, t) = 7sin(3x - 2.5t) + 7sin(3x - 2.5t + π/12)

y(x, t) = 7[sin(3x - 2.5t) + sin(3x - 2.5t + π/12)]

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y(x, t) = (2*7)[cos(π/24)sin(3x - 2.5t + π/24)]

Therefore, when x = 0.53cm and t = 2s,

y(x, t) = (2*7)[cos(π/24)sin{(3*0.53) - (2.5*2)+ π/24}]

y(x, t) = 14 * 0.9914 * 0.0713

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