The mass of the water in the container is 10,104.00 kg.
A schematic diagram of a piston-cylinder apparatus is shown in the adjoining image.
In the above case, the atmospheric pressure applied by the piston and the weight of the piston should balance the weight of the water inside the container
Hence,
Atmospheric Pressure x Area of Piston + Mass of piston x g = Mass of water x g
101 x 10^3 x pi x (2.5 x 10^-2)^2 + 4 x 10 = Mass of water x 10
Mass of water x 10 = 101,040.001
Mass of Water = 101,040.001/10
Mass of Water = 10,104 kg
Hence, the mass of the water in the container is 10,104.00 kg.
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Based on the forces acting on the axes, the resultant moments will be (345, 400, 600 N·m)
<h3>What would be resultant moment about x-axis?</h3>= F₃ x 3
= -115 x 3
= -345 N·m
<h3>What would be resultant moment about y-axis?</h3>= F₁ x 2
= -200 x 2
= -400 N·m
<h3>What would be the resultant moment about z-axis?</h3>= F₄ x 2
= -300 x 2
= - 600 N·m
In conclusion, the resultant moment about x, y, and z axes is (345, 400, 600 N·m)
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