Answer:
a) v= 2.1 m/s
b) ω = 0.807 rad/s
Explanation
Conceptual analysis :
The dog and the merry-go- round describes a circular motion, then, the following formulas apply :
Formula (1)
v = ω *r Formula (2)
Where:
: Centripetal acceleration(m/s²)
v: linear speed or tangential (m/s)
r : radius of the circle (m)
ω : angular speed ( rad/s)
Data
r= 2.6 m
= 1.7 m/s²
Problem develpment
a) We replace data in the formula 1 to calculate the dog's linear speed(v):


v= 2.1 m/s
b)We replace data in the formula 2 to calculate the angular speed of the merry-go- round (ω).
v = ω *r
2.1 = ω *2.6
ω = 2.1/2.6
ω = 0.807 rad/s
Answer:
350 Kg
Explanation:
We use the Work Formula:
W = Force . Distance
33.000 Joules = Force . 6
Force = 5500 Newtons
Force = Mass . Acceleration
5500 = Mass . 10
Mass = 550
550 - 200 = 350 Kg
Answer:
400 N
Explanation:
Change of Kinetic Energy to Friction Wok
∆KE = W
½ x m x (v(5)² - v(3)²) = f x d
½ x 500 x (5² - 3²) = f x 10
250 x (25 - 9) = f x 10
25 x 16 = f
f = 400 N
Answer:
The acceleration motorcycle
a = 5.13 m / s²
Explanation:
Now to determine the acceleration of the motorcycle
Use the force to analysis motion
∑ F = m * a
∑ F = E - D - m*g * sin ( β ) = m * a
E = 3168 N
D = 230 N
β = 31.6 °
3168 N - 230 N - 286 kg * 9.8 m / s² * sin ( 31.6° ) = 286 kg * a
Now solve to a'
a = [ 3168 N - 230 N - 286 kg * 9.8 m / s² * sin ( 31.6° ) ] / (286 kg)
a = 5.13 m / s²