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8090 [49]
3 years ago
15

Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the constant 'k' in the factored form? 6x3 + 4x2 − 6x − 4 = 2(x +

k)(x − k)(3x + 2) k= ____________ Numerical Answers Expected!
Mathematics
2 answers:
Svetach [21]3 years ago
8 0
Your answer is k= 4x^2-10x-4/6x+4

Ksju [112]3 years ago
6 0

k = 1

I already took the exam and got this right

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Write an expression that is equivalent to
finlep [7]

Answer:

15/2r - 40; Distributive Property

Step-by-step explanation:

You can use the Distributive Property to multiply the 5 across the expression in the parentheses.

5(3/2r - 8)

5 × 3/2r = 15/2r

5 × -8 = -40

Combine.

15/2r - 40

Hope this helps!

5 0
3 years ago
The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?
MaRussiya [10]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}

~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

3 0
1 year ago
In a cylindrical wooden block with a radius of 7 cm and a height of 14 cm, hemispherical blocks with
Sunny_sXe [5.5K]

9514 1404 393

Answer:

  1372π/3 cm^3 ≈ 1436.8 cm^3

Step-by-step explanation:

The diameter and height of the cylinder are both 14 cm. The resulting solid will be a 14 cm sphere. Its volume is ...

  V = 4/3πr^3 = 4/3π(7 cm)^3 = 1372π/3 cm^3 ≈ 1436.8 cm^3

4 0
2 years ago
Does anyone know how to solve |4x+3|-9<5
elixir [45]

Answer in fraction form:   -17/4 < x < 11/4

Answer in decimal form:   -4.25 < x < 2.75

=======================================================

Work Shown:

|4x+3| - 9 < 5

|4x+3| < 5+9 .... adding 9 to both sides

|4x+3| < 14

-14 < 4x+3 <  14 .... see note at the bottom

-14-3 < 4x < 14-3 .... subtracting 3 from all sides

-17 < 4x < 11

-17/4 < x < 11/4 .... divide all sides by 4

-4.25 < x < 2.75

This says that x is between -4.25 and 2.75, but x is not equal to either endpoint.

Note: I used the rule that |x| < k becomes -k < x < k where k is a positive real number.

6 0
3 years ago
Please help me with this question!!
Bess [88]

Answer:

x=16 * cos(46)

Step-by-step explanation:

Well, first let's look at our trig identities. We can set up a cosine function using the given angle:

cos (46^{o} ) = \frac{x}{16} (adjacent/hypotenuse)

Then, multiplying both sides by 16 gives us:

x=16 * cos(46)

Hope this helps!

4 0
3 years ago
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