6x^2 + 4(x^2 - 1) =
6x^2 + 4x^2 - 4 =
10x^2 - 4 <===
It should be B If I am correct if I am not I am sorry
Answrer
Find out the what is the perimeter of the rectangle .
To prove
Now as shown in the figure.
Name the coordinates as.
A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .
In rectangle opposite sides are equal.
Thus
AB = DC
AD = BC
Formula
![Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}](https://tex.z-dn.net/?f=Disatnce%5C%20formula%20%3D%20%5Csqrt%7B%28x_%7B2%7D%20-%20x_%7B1%7D%29%5E%7B2%7D%20%2B%28y_%7B2%7D%20-%20y_%7B1%7D%29%5E%7B2%7D%7D)
Now the points A(−3, 4) and B(7, 2)
![AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B%287-%20%28-3%29%29%5E%7B2%7D%20%2B%282-%204%29%5E%7B2%7D%7D)
![AB = \sqrt{(10)^{2} +(-2)^{2}}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B%2810%29%5E%7B2%7D%20%2B%28-2%29%5E%7B2%7D%7D)
![AB = \sqrt{100+4}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B100%2B4%7D)
![AB = \sqrt{104}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B104%7D)
![AB = 2\sqrt{26}\units](https://tex.z-dn.net/?f=AB%20%3D%202%5Csqrt%7B26%7D%5Cunits)
Thus
![CD= 2\sqrt{26}\units](https://tex.z-dn.net/?f=CD%3D%202%5Csqrt%7B26%7D%5Cunits)
Now the points
A (−3, 4) , D (−4, −1)
![AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}](https://tex.z-dn.net/?f=AD%20%3D%20%5Csqrt%7B%28-4%20-%20%28-3%29%29%5E%7B2%7D%20%2B%28-1-%204%29%5E%7B2%7D%7D)
![AD = \sqrt{(-1)^{2} +(-5)^{2}}](https://tex.z-dn.net/?f=AD%20%3D%20%5Csqrt%7B%28-1%29%5E%7B2%7D%20%2B%28-5%29%5E%7B2%7D%7D)
![AD = \sqrt{1 + 25}](https://tex.z-dn.net/?f=AD%20%3D%20%5Csqrt%7B1%20%2B%2025%7D)
![AD = \sqrt{26}\units](https://tex.z-dn.net/?f=AD%20%3D%20%5Csqrt%7B26%7D%5Cunits)
Thus
Formula
Perimeter of rectangle = 2 (Length + Breadth)
Here
![Length = 2\sqrt{26}\ units](https://tex.z-dn.net/?f=Length%20%3D%202%5Csqrt%7B26%7D%5C%20units)
![Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})](https://tex.z-dn.net/?f=Perimeter%5C%20of%5C%20rectangle%20%3D%202%282%5Csqrt%7B26%7D%20%2B%5Csqrt%7B26%7D%29)
![Perimeter\ of\ rectangle = 2(3\sqrt{26})](https://tex.z-dn.net/?f=Perimeter%5C%20of%5C%20rectangle%20%3D%202%283%5Csqrt%7B26%7D%29)
![Perimeter\ of\ rectangle = 6\sqrt{26}](https://tex.z-dn.net/?f=Perimeter%5C%20of%5C%20rectangle%20%3D%206%5Csqrt%7B26%7D)
![\sqrt{26} = 5.1 (Approx)](https://tex.z-dn.net/?f=%5Csqrt%7B26%7D%20%3D%205.1%20%28Approx%29)
![Perimeter\ of\ rectangle = 6\times 5.1](https://tex.z-dn.net/?f=Perimeter%5C%20of%5C%20rectangle%20%3D%206%5Ctimes%205.1)
Perimeter of a rectangle = 30.6 units.
Therefore the perimeter of a rectangle is 30.6 units.
Answer:
It has no perfect square factors, unless you count 1 = 1^2. That's sort of a degenerate case we don't usually count, since every integer has that factor. We would usually say that 1290 is a square-free integer. Hope this helps!!
Answer:9.072×10³
Step-by-step explanation:
A number is said to be written in a scientific notation or standard form if it is expressed in the form a×10n where 1 is less than or equal to a and a is less than 10 and n is an integer
9072 is more than 10
So 9072÷10=907.2
Still 907.2 is more than 10
So 907.2÷10=90.72
Still 90.72 is more than 10
So 90.72÷10=9.072
9.072 is less than 10
We divided 9072 by 1000 and 1000 as a power of ten is 10³
So the answer is 9.072×10³