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3 years ago

How do i figure out the net force of an object? explain please :)

1 answer:

3 0

Draw a free body diagram to help you visualize. draw the object and use arrows to label and determine where all the forces acting upon it will be. then u add up the sum of all forces. if two forces of equal magnitude and opposite directions will cancel each other out.

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A man tries to push a 200 kg Car that moves at a acceleration 0.50 m/s2. The man is able to displace the car 10 m. How much work

yawa3891 [41]

The work done by the man pushing the car over the given distance is 1000J.

Given the data in the question;

Mass of car; $m = 200kg$

Acceleration of the car; $a = 0.5m/s^2$

Distance covered by the car; $d = 10m$

Work done; $W = \ ?$

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

$Work\ done = f * d$

Where f is force applied and d is distance travelled.

To determine the work done by the man, we first solve for the force applied F.

From Newton's Second Law; $Force \ F = m * a$

We substitute our given values into the expression

$F = m * a \\\\F = 200kg * 0.5m/s^2\\\\F = 100kg.m/s^2$

Next we substitute our values into the expression of work done above.

$Work \ done = f * d\\\\Work \ done = 100kg.m/s^2 * 10m\\\\Work \ done = 1000kgm^2/s^2\\\\Work \ done = 1000J$

Therefore, the work done by the man pushing the car over the given distance is 1000J.

Learn more about work done: brainly.com/question/26115962

7 0

2 years ago

QUESTION 2

Mariana [72]

Question 2: Protons
Question 3: Electrons
Question 4: Protons
Question 5: Im pretty sure its electrons

8 0

4 years ago

Read 2 more answers

Lillian (mass 40.0 kg) standing at rest on slippery ice catches her leaping dog (mass 15 kg) moving horizontally at 3.0 m/s. Wha

mestny [16]

Answer:

0.82 m/s

Explanation:

From the law of conservation of momentum,

Total momentum = Final momentum.

mu+m'u' = V(m+m')......................... equation 1

Where m = mass of Lillian, u = initial velocity of Lillian before she catches the dog, m' = mass of the dog, u' = initial velocity of the dog, V = velocity of Lillian and the dog.

make V the subject of the equation,

V = (mu+m'u')/(m+m')................ Equation 2

Given: m = 40 kg, m' = 15 kg, u = 0 m/s (Lillian was standing at rest), u' = 3.0 m/s.

Substitute into equation 2

V = (40×0+15×3)/(40+15)

V = (0+45)/55

V = 45/55

V = 0.82 m/s

3 0

4 years ago

A running shoe company wants to sponsor the fastest 5% of runners. You know that in this race, the running times are normally di

pogonyaev

Answer:

We need a time of 8.118 minutes or higher in order to be sponsored by the company

Explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the running times of a population, and for this case we know the distribution for X is given by:

$X \sim N(7.2,0.56)$

Where $\mu=7.2$ and $\sigma=0.56$ minutes.

And we want the fastest 5% of runners, so we need a value a such that:

$P(X>a)=0.05$ or $P(X$

We need on the right tail of the distribution a value a that gives to us 95% of the area below and 5% of the area above. Both conditions are equivalent.

Let's use the condition $P(X$ , the best way to solve this problem is using the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

So we need a value from the normal standard distribution that accumulates 0.95 of the area on the left and 0.05 on the right. This value on this case is 1.64 and we can founded with the following code in excel:

"=NORM.INV(0.95,0,1)"

If we apply the z score formula to our case we have this:

$P(X$