The equation to be used is written as:
ρ = nA/VcNₐ
where
ρ is the density
n is the number of atoms in unit cell (for FCC, n=4)
A is the atomic weight
Vc is the volume of the cubic cell which is equal to a³, such that a is the side length (for FCC, a = 4r/√2, where r is the radis)\
Nₐ is Avogradro's constant equal to 6.022×10²³ atoms/mol
r = 0.1387 nm*(10⁻⁹ m/nm)*(100 cm/1m) = 1.387×10⁻⁸ cm
a = 4(1.387×10⁻⁸ cm)/√2 = 3.923×10⁻⁸ cm
V = a³ = (3.923×10⁻⁸ cm)³ = 6.0376×10⁻²³ cm³
ρ = [(4 atoms)(195.08 g/mol)]/[(6.0376×10⁻²³ cm³)(6.022×10²³ atoms/mol)]
ρ = 21.46 g/cm³
Answer:
if the frequency of the wave if tripled then period of wave gets tripled
Answer:
![F=1N](https://tex.z-dn.net/?f=F%3D1N)
Explanation:
Conceptual analysis
To solve this problem we apply Newton's second law:
The acceleration of an object is proportional to the force F acting on it and inversely proportional to its mass m.
a = F / m
Where,
F = m * a Formula (1)
F: Force in Newtons (N)
m: mass in kg
a: acceleration in m/(s^2)
a = v / t Formula (2)
v: speed in m/s
t: time in seconds (s)
Known information
We know the following data:
m = 1kg
v = 1 m/s
t = 1s
Development of the problem:
In the Formula (2): ![a = \frac{\frac{1m}{s}}{1s} = 1 \frac{m}{s^2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%5Cfrac%7B1m%7D%7Bs%7D%7D%7B1s%7D%20%3D%201%20%5Cfrac%7Bm%7D%7Bs%5E2%7D)
In the Formula (1): ![F=1kg* 1 \frac{m}{s^2}=1N](https://tex.z-dn.net/?f=F%3D1kg%2A%201%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%3D1N)
Answer:
The amount of heat or moisture in the air
Explanation:
Or a switch
Answer:
HERE IS YOUR ANSWER
Explanation:
PLEASE MARK MY ANSWER AS BRAINLIEST IF THE ANSWERS ARE CORRECT .
Beacuse of the loose connection of the wire .
Straight