Answer:
Q = 19255.6 j
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Given data:
Mass of water = 46 g
change in temperature = ΔT = 100-0.0 = 100 °C
Heat absorbed by water = ?
Solution:
Specific heat capacity of water = 4.186 j/g. °C
Q = m.c. ΔT
Q = 46 g×4.186 j/g. °C×100 °C
Q = 19255.6 j
