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Assoli18 [71]
3 years ago
10

PLEASE HURRY THIS IS TIMED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
1 answer:
AURORKA [14]3 years ago
5 0

Answer:

if i remember correctly i beleive its A  1.8 x 10^24

but im not for sure  also i think you forgot the 24

Explanation:

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Write a word equation for the chemical reaction.<br><br> I’ll brainlist.
Alex

Answer:

potassium hydroxide + sulfuric acid → potassium sulfate + water.

Explanation:

Hope it helps.. if yes, plz mark me as brainliest

5 0
3 years ago
Determine Δngas for each of the following reaction:(b) 2PbO(s) + O₂(g) ⇄ 2PbO₂(s)
Elis [28]

2PbO(s) + O₂(g) ⇄ 2PbO₂(s)

Then Δngas = -1

<h3>What is Δngas?</h3>

The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.

Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.

<h3>Definition of equilibrium</h3>

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Learn more about Equilibrium

brainly.com/question/11336012

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5 0
2 years ago
For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi
natka813 [3]

<u>Answer:</u> The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ....(1)

  • <u>For Iron:</u>

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:  

\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol

For the given chemical reaction:

2Fe(s)+O_2(g)\rightarrow 2FeO(s)

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = \frac{2}{2}\times 0.0771=0.0771mol of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:  

0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g

To calculate the percentage yield of iron (ii) oxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0
3 years ago
PLEASE HELP ME Which of the following is a Brønsted-Lowry base but not an Arrhenius base?
never [62]
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4 0
3 years ago
What is the molecule that senses heat stress in a cell?
nlexa [21]

Answer: -

sigma factor mRNA RpoH sigma H sigma 32

Explanation: -

It is the heat shock sigma factor which activates due to heat. The factor will bind with to the polymerase-core-enzyme. After this other heat ans shock proteins are expressed.

This thus enable the cell to survive higher temperatures. Some of the enzymes that are expressed upon activation are chaperones, proteases and DNA-repair enzymes

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