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mote1985 [20]
4 years ago
6

When the glucose solution described in part A is connected to an unknown solution via a semipermeable membrane, the unknown solu

tion level rises. Based on this information, what can be said about these two solutions?
1. The unknown solution had the lower concentration.
2. The unknown solution had the higher concentration.
3. The two solutions have the same concentration.
Chemistry
1 answer:
olya-2409 [2.1K]4 years ago
7 0

Answer: The unknown solution had the lower concentration

Explanation: concentration will always move from higher to lower region. If the concentration of the unknown solution has increased, it therefore means that the initial concentration of the unknown solution was low

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3 years ago
PLEASE HELP ASAP
Nady [450]

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4 years ago
Read 2 more answers
A 13.5 g sample of an unknown gas occupies 5.10 L at 149.83 kPa and 301 K. What is the molar mass of the gas ?
alisha [4.7K]

Answer:

The molar mass of the gas is 44.19 g/mol

Explanation:

Amount of sample of gas = m = 13.5 g

Volume occupied by the gas = V = 5.10 L

Pressure of the gas = P = 149.83 KPa

1 KPa = 0.00986 atm

P = 149.83 \textrm{ KPa} \times 0.00986 \textrm{ atm/KPa} = 1.48 \textrm{ atm}

Assuming M g/mol to be the molar mass of the gas

Assuming the gas is behaving as an ideal gas

\textrm{PV} =\textrm{nRT} \\\textrm{PV} = \displaystyle \frac{m}{M}\textrm{ RT } \\1.48 \textrm{ atm}\times 5.10 \textrm{ L} = \displaystyle \frac{13.5 \textrm{ g}}{M}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 301\textrm{K} \\M = 44.19 \textrm{ g/mol}

The molar mass of gas is 44.19 g/mol

7 0
4 years ago
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