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2 years ago

How many moles of ions are produced by ionization of 2 moles of MgCl2

Chemistry

1 answer:

tensa zangetsu [6.8K]2 years ago

3 0

Answer:

number of ions = 12.04 x 10^²³

Explanation:

n = number of ions/Avogadro's constant

2 = number of ions/6.02 x 10^²³

number of ions= 2 x 6.02 x 10^²³

number of ions = 12.04 x 10^²³

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Explanation:

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3 years ago

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Exactly 16 mL of a solution A is diluted to 300 mL, resulting in a new solution B that has 0.50 M concentration. If the solution

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Answer:

8.77g

Explanation:

Step 1:

Data obtained from the question.

This includes the following:

Concentration of A (C1) =.?

Volume of A (V1) = 16 mL

Volume of B (V2) = 300 mL

Concentration of B (C2) = 0.50 M

Molar Mass of NaCl = 58.443 g/mol

Mass of NaCl =.?

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Determination of the concentration of A.

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C1V1 = C2V2

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Divide both side by 16

C1 = (0.5 x 300) / 16

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Therefore, the concentration of A is 9.375 M

Step 3:

Determination of the number of mole of NaCl in 9.375 M NaCl solution. This is illustrated below:

Molarity = 9.375 M

Volume = 16 mL = 16/1000 = 0.016 L

Mole of NaCl =?

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Step 4:

Determination of the mass of NaCl. This is illustrated below:

Mole of NaCl = 0.15 mole

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Mass of NaCl =?

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3 years ago

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A chemical reaction occurring in a cylinder equipped with a moveable piston produces 0.641 mol of a gaseous product. If the cyli

snow_tiger [21]

<u>Answer:</u> The final volume of the reaction is 4.69 L

<u>Explanation:</u>

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The equation used to calculate number of moles is given by:

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

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$V_1\text{ and }n_1$ are the initial volume and number of moles

$V_2\text{ and }n_2$ are the final volume and number of moles

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<em>...Dissolves 15.0g of styrene (C₈H₈) in 250.mL of a solvent with a density of 0.88g/mL...</em>

<em />

Molarity is defined as moles of solute (Styrene in this case) per liter of solution whereas molality is the moles of solute per kg of solvent. Thus, we need to find the moles of styrene, the volume in liters of the solution and the mass in kg of the solvent as follows:

<em>Moles styrene:</em>

Molar mass C₈H₈:

8C = 12.01g/mol*8 = 96.08g/mol

8H = 1.005g/mol* 8 = 8.04g/mol

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15.0g * (1mol / 104.12g) = 0.144 moles of styrene

<em>Liters solution:</em>

250mL * (1L / 1000mL) = 0.250L

<em>kg solvent:</em>

250mL * (0.88g/mL) * (1kg / 1000g) = 0.220kg

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