Answer:
Option B. is the right answer.
Explanation:
Before developing a new technology, an engineer has to evaluate the advantages and disadvantages of the chemical used in order to clean water bodies. If the chemical has more disadvantages as compared to advantages, so its usage will be avoided while if the chemical does not harm the marine organisms of the ocean so it can be used for the purpose of cleaning. So we can say that first the engineer has to study the chemicals.
Answer:
mass of water in hydrate = 2.37 grams
Explanation:
The mass of the hydrated cobalt (III) chloride is the summation of the salt and the water it contains.
This means that:
Total mass of sample = mass of salt + mass of water
Now, we are given that:
total mass of sample = 5.22 grams
mass of salt = mass of sample after heating = 2.85 grams
Substitute to get the mass of water as follows:
5.22 = mass of water in hydrate + 2.85
mass of water in hydrate = 5.22 - 2.85
mass of water in hydrate = 2.37 grams
Hope this helps :)
Answer:
16Ag + 2C2 ---> 4 Ag4C
Explanation:
Ag + C2 ----> AgC2
The valence of Ag is one
Valence of Carbon is four
A balanced equation would be
16Ag + 2C2 ---> 4 Ag4C
Answer: the density of the solid metal is 22.5176 g/cm
Explanation:
Given that;
mass of solid metal = 255 g
the cylinder and its contents weigh 101g less than before
also given that density of mercury = 13.6 g/cm³
Volume of the solid metal = volume of mercury which was absent in the first weighing
so let volume = Vcm³
Mass of mercury which was absent in the first weighing = density × volume
= 13.6 g/cm³ × Vcm³ = 13.6V g
now since the cylinder and its contents weigh 101g less than before,
it means the difference in mass between the solid and metal and the mass of mercury is equal to 101 g
so
255 - 13.6V g = 101g
13.6V g = 255 g - 101 g
13.6V = 154
V = 154 / 13.6
V = 11.3245 cm³
Now Density of solid metal will be;
⇒ mass / volume
= 255 / 11.3245
= 22.5176 g/cm
Therefore, the density of the solid metal is 22.5176 g/cm
