To calculate the mass of Fe formed in a) we get first the limiting reactant between Fe2O3 and CO. Given the masses, the ratio of Fe2O3 is 1.33 while that of CO is 1.67. Hence the limiting reagent is Fe2O3. The mass of Fe formed is 148.98 grams. In b, the needed CO is only 112.04 grams. Hence, the excess is 27. 96 grams.
Data:
F (force) = 22.0 N
m (mass) = ? (in Kg)
a (acceleration) = 5.5 m/s²
We apply the data to the Resultant Force formula, we have:
4.0 kg
I hope this helps. =)
