Answer:

Explanation:
Given that
T₁ = 290 K
P₁ = 100 KPa
Power P =5.5 KW
mass flow rate

Lets take the exit temperature = T₂
We know that


If we assume that process inside the compressor is adiabatic then we can say that





That is why the exit pressure will be 4091 KPa.
The pressure of nitrogen which is needed to maintain a N2 concentration of 0. 53 m is 3.2 × 10^(4).
<h3>What is pressure? </h3>
It is defined as the continuous physical force applied on or against an object by something which is in contact with it.
It is also defined as the force per unit area.
<h3>What is henry's law? </h3>
The henry law constant is thr ratio of the partial pressure of compound in air to the concentration of compound in water at given temperature.
C= kp
where,
C is the concentration of compound = 0.53m
k is the henry constant = 6. 2×10−4matm
p is the pressure of compound
By substituting all the value we get,
C = 6. 2×10−4 × p
0.53 = 6. 2×10−4 × p
p = 0.53/6. 2×10−4
p = 3.2 × 10^(4)
Thus we find that the pressure needed to maintain a N2 concentration of 0. 53 m is 3.2 × 10^(4).
learn more about Henry's law:
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Answer:
The velocity when the ball hits the ground is obtained using v2. 2 = v1. 2 + 2 g Dy with v1=0 and Dy=h. Thus solving for v2 yields 17.1 m/s v2 = 2 g h =.
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The incline is frictionless, this means we can use the conservation of energy: the initial kinetic energy of the block

is converted into gravitational potential energy

where h is the height reached by the block as it stops. By equalizing the two formulas, we get


However, this is the maximum height reached by the block. The distance along the surface of the plane is given by:
It can be said that most of the required information's are already given in the question.
Let us assume the speed of the passenger train = x
Speed of the freight train = y
x = y + 40
The second equation will be
6 * x = 10 * y
6x = 10y
Dividing both sides by 2, we get
3x = 5y
x = 5y/3
Putting the value of "x" in the first equation, we get
x = y + 40
5y/3 = y + 40
5y = 3y + 120
5y - 3y = 120
2y = 120
y = 60 mph
Putting the value of y in the first equation, we get
x = y + 40
= 60 + 40
= 100 mph
From the above deduction, we can conclude that the passenger train is traveling at 100 mph and the freight train is traveling at 60 mph.