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ivanzaharov [21]
3 years ago
15

A 5.0 cm object is 12.0 cm from a concave mirror that has a focal length of 24.0 cm. The distance between the image and the mirr

or is __________ *
1 point
12cm
24cm
5cm
8cm
Physics
2 answers:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

The answer is 24cm

Explanation:

This problem bothers on the curved mirrors, a concave type

Given data

Object height h= 5cm

Object distance = 12cm

Focal length f=24cm

Let the image distance be v=?

Applying the formula we have

1/v +1/u= 1/f

Substituting our given data

1/v+1/12=1/24

1/v=1/24-1/12

1/v=1-2/24

1/v=-1/24

v= - 24cm

This implies that the image is on the same side as the object and it is real

blsea [12.9K]3 years ago
3 0

Answer:

24 cm or -24 cm

Explanation:

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Nostrana [21]

Answer:

Option B

the type of light and the material of the lens

Explanation:

Since the experiment focuses on investigating how thickness of a lens affects the point where a beam of light, it means thickness of lens here are indepedent variable since Lydia has control over the thickness and can alter it. However, the point where beam of light focuses on is depedent variable since Lydia will just observe the point but can't change it. To ensure that other external factors don't affect the results, Lydia has to ensure that the type of material irrespective of thickness remain constant and also the source of light must be kept constant. Therefore, the controls will be the type of light and the material of the lens

4 0
3 years ago
A horizontal platform in the shape of a circular disk rotates on a frictionless bearing about a vertical axle through the center
Bess [88]

Answer:

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Explanation:

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Similarly, we can calculate the system moment of inertia when she's at 0.456 m from the center

I_2 = I_d + 67.8*0.456^2 = 274 + 14.1 = 288.1 kgm^2

We can apply the law of angular momentum conservation to calculate the post angular speed when she's 0.456m from the center:

I_1\omega_1 = I_2\omega_2

\omega_2 = \omega_1\frac{I_1}{I_2} = 2.62*\frac{1202.182}{288.1} = 10.93 rad/s

8 0
3 years ago
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zhuklara [117]

Answer:

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Explanation:

just took the test

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vladimir2022 [97]

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