A. a higher boiling point and a lower freezing point
Explanation:
hope this helps :)
The convection current is one of hot air rising, in this example, and then cooling and returning down. The rising air pushes the eagle up higher into the air. It just has to spread its wings and let the air push it into the air
When a mixture of 10 moles of SO2 and 15 moles of O2 was passed over a catalyst, 10 moles of SO3 was formed.
Answer:
60.052 g/mol (molar mass of vinegar)
84.007g/mol (baking soda )
Answer:
94.2 g/mol
Explanation:
Ideal Gases Law can useful to solve this
P . V = n . R . T
We need to make some conversions
740 Torr . 1 atm/ 760 Torr = 0.974 atm
100°C + 273 = 373K
Let's replace the values
0.974 atm . 1 L = n . 0.082 L.atm/ mol.K . 373K
n will determine the number of moles
(0.974 atm . 1 L) / (0.082 L.atm/ mol.K . 373K)
n = 0.032 moles
This amount is the weigh for 3 g of gas. How many grams does 1 mol weighs?
Molecular weight → g/mol → 3 g/0.032 moles = 94.2 g/mol
