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Vanyuwa [196]
4 years ago
5

X why is cyano group called as anambident group?​

Chemistry
1 answer:
Ira Lisetskai [31]4 years ago
3 0

Answer:

Both the C and the N can participate in reactions  

Explanation:

The word ambident comes from two Latin words that mean "both teeth".

An ambident group can react at two different sites to form products.  

For example, the cyano group has two major resonance structures (see below).

The hybrid has two different ends, each with a lone pair and a partial negative charge.

Thus, it can react to form CH₃CN by having the C attack, or CH₃NC by having the N attack.

You might be interested in
PLEASE HELP! Find out whether the chemical equation is balanced or unbalanced.
nordsb [41]

One chemical reaction is called the Haber process, a method for preparing ammonia by reacting nitrogen gas with hydrogen gas:


This equation shows you what happens in the reaction, but it doesn’t show you how much of each element you need to produce the ammonia. To find out how much of each element you need, you have to balance the equation — make sure that the number of atoms on the left side of the equation equals the number of atoms on the right.


You know the reactants and the product for this reaction, and you can’t change them. You can’t change the compounds, and you can’t change the subscripts, because that would change the compounds.


So the only thing you can do to balance the equation is add coefficients, whole numbers in front of the compounds or elements in the equation. Coefficients tell you how many atoms or molecules you have.


For example, if you write the following, it means you have two water molecules:


Each water molecule is composed of two hydrogen atoms and one oxygen atom. So with two water molecules (represented above), you have a total of 4 hydrogen atoms and 2 oxygen atoms.


You can balance equations by using a method called balancing by inspection. You take each atom in turn and balance it by adding appropriate coefficients to one side or the other.


With that in mind, take another look at the equation for preparing ammonia: HOPE THIS HELPS



4 0
3 years ago
Suppose you have 300.0 mL of a 0.1000 M solution of a strong acid (HCl), and you add this to 100.0 mL of a 0.0200 M solution of
Ganezh [65]

Answer:

ph=150.0ml

Explanation:

BOy im on you boy

5 0
3 years ago
Help in my exam plzz now​
swat32

Answer:

yes your answer is correct

I hope it helps mate

I will always help you understanding your assingments have a great day

#Captainpower:)

8 0
3 years ago
34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases
Digiron [165]

Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

<em>Where q is heat of reaction in J,</em>

<em>m is the mass of the solution in g,</em>

<em>S is specific heat of the solution = 4.184J/g°C</em>

<em>ΔT is change in temperature = 11.21°C</em>

The mass of the solution is obtained from the volume and the density as follows:

150.0mL * (1.20g/mL) = 180.0g

Replacing:

q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

q = 8.44kJ when 3.15 moles of the solid react.

The ΔH of the reaction is:

8.44kJ/3.15 mol

= 2.68kJ/mol

5 0
3 years ago
Nail polish remover containing acetone was spilled in a room 7.2 m × 5.8 m × 3.9 m. Measurements indicated that 6,400 mg of acet
sergeinik [125]

Volume of room  = 7.2 m \times 5.8 m \times  3.9 m

= 162.864 m^{3}

Now, according to conversion factor, convert 6,400 mg to micrograms

Since, 1 mg is equal to 1000 microgram.

Therefore, 6,400 mg  = 6,400 \times 1000

= 6,400,000 micrograms of acetone.

To calculate concentration of acetone, divide volume and evaporated amount of acetone in micrograms.

Thus,

Concentration of acetone  = \frac{6,400,000 microgram}{162.864 m^{3}}

= 39296.5910 microgram per cubic meter or 3.92\times 10^{4} \mu g/m^{3}\simeq 4.0\times 10^{4} \mu g/m^{3}

Hence, concentration of acetone is equal to 4.0\times 10^{4} \mu g/m^{3}

7 0
3 years ago
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