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Nady [450]
3 years ago
15

Given line m is parallel to line n. What theorem or postulate justifies the statement? ∠1 ≅ ∠4

Mathematics
1 answer:
natima [27]3 years ago
6 0

Answer:

corresponding angles postulate

Step-by-step explanation:

just took the test ;)

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Find the inverse of the given relation. {(9, –14), (–7, 4), (6, –8)}
Law Incorporation [45]

Answer:

{(-14,9),(4,-7),(-8,6)}.

Step-by-step explanation:

To find the inverse you just swap x and y.

So if (a,b) is a point on the relation then (b,a) is on it's inverse.

So the inverse of {(9, –14), (–7, 4), (6, –8)} is:

{(-14,9),(4,-7),(-8,6)}.

7 0
3 years ago
Simplify the following expression into the form a + bi, where a and b are rational numbers.
vagabundo [1.1K]
The answer is -16 - 10i.

Using the distributive property on the first part, we have:
-2i*7--2i*4i + (3+i)(-2+2i)
-14i+8i² +(3+i)(-2+2i)

Using FOIL on the last part,
-14i+8i²+(3*-2+3*2i+i*-2+i*2i)
-14i+8i²-6+6i-2i+2i²
-10i+8i²-6+2i²

Since we know that i = -1,
-10i+8(-1)-6+2(-1)
-10i-8-6-2
-16-10i
7 0
2 years ago
Read 2 more answers
Marcus boxers dog 3/5 of a mile every day how far does Marcus walk his dog 6 days
lina2011 [118]
Marcus walks 3.5 miles
6 0
3 years ago
100 POINTS!!!!
weeeeeb [17]

Answer:

O is the center of the circle with radius IE(=ID=EF)

Step-by-step explanation:

Join all 3 points D, E, F, forming the triangle DEF.

Let the midpoint of EF be M and the midpoint of ED be N. (first picture)

Join point I to E, D and F.

Since IN is both an altitude and median to triangle EID, then triangle EID is an isosceles triangle, and IE=ID

similarly, we see that IE=IF.

conclusion: IE=ID=EF.

5 0
2 years ago
Read 2 more answers
Find the indicated probability.
natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

<u>Recall:</u>

  • Binomial Distribution --> P(k)={n\choose k}p^kq^{n-k}
  • P(k) denotes the probability of k successes in n independent trials
  • p^k denotes the probability of success on each of k trials
  • q^{n-k} denotes the probability of failure on the remaining n-k trials
  • {n\choose k}=\frac{n!}{(n-k)!k!} denotes all possible ways to choose k things out of n things

<u>Given:</u>

  • n=10
  • k=4
  • p^k=0.53^4
  • q^{n-k}=(1-0.53)^{10-4}=0.47^6
  • {n\choose k}={10\choose 4}=\frac{10!}{(10-4)!4!}=210

<u>Calculate:</u>

  • P(4)=(210)(0.53^4)(0.47^6)=0.1786117069\approx0.179

Therefore, the probability that the archer will get exactly 4 bull's-eyes with 10 arrows in any order is 0.179

7 0
2 years ago
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