A spherical hot air balloon of diameter 30.0 meters just floats (hovers) when the hot air inside has been heated to a density of
1 answer:
Answer:
W = 166422.729 N
Explanation:
given,
diameter of the balloon = 30 m
density of the air = 1.10 Kg/m³
weight of the balloon and cargo = ?
density of the surrounding air = 1.20 kg/m³
we know,
Density = mass/volume
m = density x volume
m = 16964.6 Kg
Weight of the balloon
W = m g
W = 16964.6 x 9.81
W = 166422.729 N
Weight of the balloon and the cargo is equal to W = 166422.729 N
You might be interested in
Answer:
3.59 m/s
Explanation:
The average velocity is defined as:
The turtle first walks 18m south, and then is taken 1,1Km (or 1100m) north. Thus, the total displacement is 1082m north (1100m north - 18m south).
Now we have to calculate the total time, which will be equal to the sum of the time the turtle walked and the time it was taken by truck.
The walking time is 3.5 minutes. Since 1 minute = 60 seconds, then the walking time is 210 seconds.
To calculate the truck time we use the equation:
Time =
Where the distance the truck travelled is 1100m and the speed of the truck is 12m/s.
Thus,
Truck time= = 91.67s
The total time is the sum of the walking time and the truck time.
Total time = 210s + 91.67s = 301.67s.
As mencioned previously, the average velocity is equal to total displacement/ total time, thus:
Average velocity = = 3.59 m/s North
Since the average velocity is a vector, it has a magnitude and a direction. In this case the magnitude is 3.59 m/s and the direction is north since the turtle's final displacement is north of where it started.
Answer:
(a). The work done is 7001 MeV.
(b). The momentum of this proton is .
Explanation:
Given that,
Speed = 0.993 c
We need to calculate the work done
Using work energy theorem
The work done is equal to the kinetic energy relative to the proton
Put the value into the formula
(b). We need to calculate the momentum of this proton
Using formula of momentum
Put the value into the formula
Hence, (a). The work done is 7001 MeV.
(b). The momentum of this proton is .