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finlep [7]
3 years ago
10

A spherical hot air balloon of diameter 30.0 meters just floats (hovers) when the hot air inside has been heated to a density of

1.10 kg/m3 What is the weight of the balloon and cargo (not including the air inside) if the surrounding air has a density of 1.20 kg/m3? (VSphere = (4/3)nr3)
Physics
1 answer:
Rom4ik [11]3 years ago
5 0

Answer:

W = 166422.729 N

Explanation:

given,

diameter of the balloon = 30 m

density of the air = 1.10 Kg/m³

weight of the balloon and cargo = ?

density of the surrounding air = 1.20 kg/m³

we know,

Density = mass/volume

m = density x volume

m = \rho\times \dfrac{4}{3}\pi r^3

m =1.20 \times \dfrac{4}{3}\pi\times 15^3

m = 16964.6 Kg

Weight of the balloon

 W = m g

 W = 16964.6 x 9.81

W = 166422.729 N

Weight of the balloon and the cargo is equal to  W = 166422.729 N

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1 point
Tju [1.3M]

Answer:

Option A nuclear

Explanation:

The rate of electricity production in nuclear power plant is much higher as compared to the rate of electricity generation in gas, wind and solar power plants.

Thus, in case where large amount of electricity is to be produced in a short period then one must rely on nuclear power plants.

Therefore, option A is correct

7 0
3 years ago
Light travels from medium X into medium Y. Medium Y has a higher index of refraction. Consider each statement below:(i) The ligh
ahrayia [7]

Answer:

i) FALSE,  ii) TRUE,  iii) FALSE, iv)  FALSE

Explanation:

When light (electromagnetic radiation) travels through a material medium, its speed is less than the speed of light in a vacuum. If we define the index of parts

           n = c / v

where v is the speed of light in the material medium.

The direction of the ray can be determined by the law of refraction

          n₁ sin θ₁ = n₂ sin θ₂

Let's apply these equations to our case where

          nₓ <n_y

i) The expression of the refractive index

          nₓ < n_y

         \frac{c}{v_x} = \frac{c}{n_y}

         v_y <vₓ

therefore the expression is FALSE

ii) If we use the law of refraction, the light, when passing from a medium with a lower start to another with a higher index, must approach the normal one, away from what would be the continuation of the path of the incident ray

so the expression is TRUE

iii) The speed of light is constant in all material media

the statement is FALSE

iv) light approaches normal

Let me clarify that the normal is a line perpendicular to the surface at the point of contact, not the direction of Io.

 the statement of FALSE

8 0
3 years ago
Identify the differences between the dfss (design for six sigma) and the dmaic (define, measure, analyze, improve, control) proc
s344n2d4d5 [400]

The difference between the dfss (design for six sigma) and the dmaic (define, measure, analyze, improve, control) processes only lies in the analyzing stage. To further avert problems, DFSS requires market research data, customer complaints about the product, and attempts to rebuild a new product.

The primary distinction is that DMAIC is a technique that emphasizes making changes to the organization's current goods and services.

On the other hand, DFSS strives to create a new, defect-free good or service that satisfies CTQ requirements and results in customer satisfaction.

Design for Six Sigma (DFSS) is an improvement process that aids companies in producing high-quality new goods and services.

The technique tries to satisfy client expectations while making the most of the company's capabilities during the initial development of a process.

A data-driven quality technique called Define, Measure, Analyze, Improve, and Control (DMAIC) is used to enhance processes.

Learn more about DMAIC here brainly.com/question/6352959

#SPJ4

3 0
2 years ago
The drawing shows three identical springs hanging from the ceiling. Nothing is attached to the first spring, whereas a 4.5 n blo
Naya [18.7K]

<Continuation of the question>

(a) the spring constant (in N/m) and

(b) the weight of the block hanging from the third spring.

the distance for the first spring is 20cm, the second 35cm, the third 50cm.

Answer:

a) To find the spring constant, we'll use the formula

F=kx, if we make k the subject we'll get

k=F/x, where F=4.5N, x = 35cm - 20cm = 15cm = 0.15m

k=F/x = 4.5N/0.15m =  30N/m is the Answer

b) to find the weight of block hanging on third spring

we use the formula F=kx

where k = 30N/m, x=50cm-20cm=30cm=0.30m

F=kx = (30N/m)*(0.30m) = 9N  is the Answer

4 0
3 years ago
If an astronomical object's parallax is one-half arcsecond, how many parsecs is it from Earth?
Mariulka [41]

thw answer is C. 2

i do not know why! Sorry!

i just took the test and it was right

6 0
3 years ago
Read 2 more answers
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