Answer:
C) 4.0026 amu
Explanation:
Helium (He) is the 2nd element on the Periodic Table.
It's neutral atom has 2 protons and 2 electrons.
It is in the 1st period and the 18th row.
It is also a Noble gas.
A spherical hot air balloon of diameter 30.0 meters just floats (hovers) when the hot air inside has been heated to a density of
1 answer:
Answer:
W = 166422.729 N
Explanation:
given,
diameter of the balloon = 30 m
density of the air = 1.10 Kg/m³
weight of the balloon and cargo = ?
density of the surrounding air = 1.20 kg/m³
we know,
Density = mass/volume
m = density x volume
m = 16964.6 Kg
Weight of the balloon
W = m g
W = 16964.6 x 9.81
W = 166422.729 N
Weight of the balloon and the cargo is equal to W = 166422.729 N
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Answer:
a. S(t)=350−1t
Explanation:
To determine the equation of motion you take into account the general form of motion with constant velocity:
( 1 )
So is the initial position from a specific reference frame. In this case is 350 m.
v is the speed of the motion, in this case is 1m/s. However, the motion is forward the zero point of the reference frame, hence, the speed is - 1m/s.
You replace the values of So and v in the equation ( 1 ) and you obtain:
Hence, the answer is:
a. S(t)=350−1t
- - - - - - - - - - - - - - - - - - - - -
Para determinar a equação do movimento, você leva em consideração a forma geral do movimento com velocidade constante:
(1)
Assim é a posição inicial de um quadro de referência específico. Neste caso, é de 350 m.
v é a velocidade do movimento, neste caso é de 1m / s. No entanto, o movimento é avançar o ponto zero do quadro de referência, portanto, a velocidade é de - 1m / s.
Você substitui os valores de So ev na equação (1) e obtém:
Portanto, a resposta é:
uma. S (t) = 350-1t, movimento retrógrado
Answer:
t = 1.42 s and d = 35.5 m
Explanation:
Given that,
Velocity of a roadrunner is 25 m/s
A certain coyote wants to capture the roadrunner using a net dropped from an overpass that is 10 m high.
We need to find the time before the roadrunner is under the overpass and how far away from the overpass is the roadrunner when the coyote drops the net.
Let d is the distance traveled. So,
d = vt
d = 25 m/s × 1.42 s
d = 35.5 m