Answer:
W = 166422.729 N
Explanation:
given,
diameter of the balloon = 30 m
density of the air = 1.10 Kg/m³
weight of the balloon and cargo = ?
density of the surrounding air = 1.20 kg/m³
we know,
Density = mass/volume
m = density x volume
m = 16964.6 Kg
Weight of the balloon
W = m g
W = 16964.6 x 9.81
W = 166422.729 N
Weight of the balloon and the cargo is equal to W = 166422.729 N
Answer:
The acceleration of the electron is 1.457 x 10¹⁵ m/s².
Explanation:
Given;
initial velocity of the emitted electron, u = 1.5 x 10⁵ m/s
distance traveled by the electron, d = 0.01 m
final velocity of the electron, v = 5.4 x 10⁶ m/s
The acceleration of the electron is calculated as;
v² = u² + 2ad
(5.4 x 10⁶)² = (1.5 x 10⁵)² + (2 x 0.01)a
(2 x 0.01)a = (5.4 x 10⁶)² - (1.5 x 10⁵)²
(2 x 0.01)a = 2.91375 x 10¹³
Therefore, the acceleration of the electron is 1.457 x 10¹⁵ m/s².
Answer:
Effective half-time of the tracer is 3.6 days
Explanation:
The formula for calculating the decay due to excretion for the first process is ;
here ;
= initial number of tracers
Then to the second process ; we have :
The total decay is as a result of the overall process occurring ; we have :
------ (1)
here ;
Putting the values in (1);we have :
As we also know that:
= 3.6 days
Answer:
The induced voltage in the coil is 0.25 V.
Explanation:
It is given that,
Area of a square coil is 2 cm or 0.02 m
Number of turns in the wire is 2500
A uniform magnetic field perpendicular to its plane is turned on and increases to 0.25 T during an interval of 1.0 s.
We need to find the induced voltage in the coil. According to Faraday's law, the induced emf in the coil is given by the rate of change on magnetic flux. So,
So, the induced voltage in the coil is 0.25 V.