Question

A 66.5-kg hiker starts at an elevation of 1270 m and climbs to the top of a peak 2660 m high.

Answer 1

Answer

given,

mass of the hiker = 66.5 kg

elevation of the hiker,h₁ = 1270 m

elevation of top peak,h₂ = 2660 m

a) Change in potential energy

    Δ PE = m g h₂ - m g h₁

    Δ PE = m g (h₂ - h₁)

    Δ PE = 66.5 x 9.8 x  (2660 - 1270)

    Δ PE = 905863 J

b) Minimum work require by the hiker will be equal to Δ PE = 905863 J

c) yes, it can be more than this, if friction is present on the surface.