Answer:
The charge resides on the outer surface = 
C
Explanation:
Surface area of cell 
Separation between two plate 
Dielectric constant 
Potential difference 
The capacitance of parallel plate capacitor in free space is given by,
Where 
permittivity of free space = 
The Capacitance of capacitor is increase by 
times when it placed in dielectric medium.
And we know that, 
So charge on the outer surface is given by,
<h2>F = kAρv²</h2>
Explained in the attachment !
<h3>Hope it helps you!!</h3>
Answer:
Calcium bromide is the name for compounds with the chemical formula CaBr2(H2O)x.
Answer:
1.925 μC
Explanation:
Charge: This can be defined as the product of the capacitance of a capacitor and the voltage. The S.I unit of charge is Coulombs (C)
The formula for the charge stored in a capacitor is given as,
Q = CV ................... Equation 1
Where Q = charge, C = Capacitor, V = Voltage.
Note: 1 μF = 10⁻⁶ F
Given: C = 0.55 μF = 0.55×10⁻⁶ F, V = 3.5 V.
Substitute into equation 1
Q = 0.55×10⁻⁶×3.5
Q = 1.925×10⁻⁶ C.
Q = 1.925 μC
Hence the charge on the plate = 1.925 μC
Answer:
Reflection is when light bounces off an object, while refraction is when light bends while passing through an object.
