Answer:
Three liters of gaseous oxygen at 15 degrees Celsius and at atmospheric pressure (1atm), is brought to a pressure of 10mm Hg. What will be the volume of the gas now if the temperature has not changed?
Explanation:
Given that, the temperature is constant
Then, using gay Lussac law
P1•V1 / T1 = P2•V2 / T2
Since temperature is constant
Then, T1 = T2 = T and they cancels out
So, we are left with
P1•V1 = P2•V2
Given that, .
Initial volume
V1 = 3 litres.
Initial pressure
P1 = 1atm = 101325 Pa
Final pressure
P2 = 10mmHg = 1333.22 Pa
Then, we want to find the final volume V2
Make V2 subject of formula.
V2 = V1•P1 / P2
V2 = 3 × 101325 / 1333.22
V2 = 288 litres
So, the final volume is 288 litres.
In Spanish
Dado que la temperatura es constante
Luego, usando la ley gay de Lussac
P1 • V1 / T1 = P2 • V2 / T2
Como la temperatura es constante
Entonces, T1 = T2 = T y se cancelan
Entonces, nos quedamos con
P1 • V1 = P2 • V2
Dado que, .
Volumen inicial
V1 = 3 litros.
Presión inicial
P1 = 1atm = 101325 Pa
Presión final
P2 = 10 mmHg = 1333.22 Pa
Entonces, queremos encontrar el volumen final V2
Hacer V2 sujeto de fórmula.
V2 = V1 • P1 / P2
V2 = 3 × 101325 / 1333.22
V2 = 288 litros
Entonces, el volumen final es de 288 litros
