4. Is the force of the earth’s gravity on the sun stronger, weaker, or the same as the force of the sun’s gravity on the earth?
1 answer:
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1. Amperes, is the SI unit (also a fundamental unit) responsible for current.
2. Δq over Δt technically
Rearrange for Δq
I x Δt = Δq
1.5mA x 5 = Δq
Δq = 0.0075
Divide this by the fundamental charge "e"
Electrons: 0.0075 / 1.60 x 10^-19
Electrons: 4.6875 x 10^16 or 4.7 x 10^16
3. So we know that the end resistances will be equal so:
ρ = RA/L
ρL = RA
ρL/A = R
Now we can set up two equations one for the resistance of the aluminum bar and one for the copper: Where 1 represents aluminum and 2 represents copper
We are looking for L2 so we can isolate using algebra to get:
If you fill in those values you get 0.0205
or 2.05 cm
1) -7.14 N
2) +2.70 N
3) 7.63 N
Explanation:
1)
In order to find the x-component of the resultant force, we have to resolve each force along the x-axis.
The first force is 8.00 N and is directed at an angle of 61.0° above the negative x axis in the second quadrant: this means that the angle with respect to the positive x axis is
so its x-component is
F₂ has a magnitude of 5.40 N and is directed at an angle of 52.8° below the negative x axis in the third quadrant: so, its angle with respect to the positive x-axis is
Therefore its x-component is
So, the x-component of the resultant force is
2)
In order to find the y-component of the resultant force, we have to resolve each force along the y-axis.
The first force is 8.00 N and is directed at an angle of 61.0° above the negative x axis in the second quadrant: as we said previously, the angle with respect to the positive x axis is
so its y-component is
F₂ has a magnitude of 5.40 N and is directed at an angle of 52.8° below the negative x axis in the third quadrant: as we said previously, its angle with respect to the positive x-axis is
Therefore its y-component is
So, the y-component of the resultant force is
3)
The two components of the resultant force representent the sides of a right triangle, of which the resultant force corresponds tot he hypothenuse.
Therefore, we can find the magnitude of the resultant force by using Pythagorean's theorem:
Where in this problem, we have:
is the x-component
is the y-component
And substituting, we find: