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vladimir2022 [97]
3 years ago
8

4. Is the force of the earth’s gravity on the sun stronger, weaker, or the same as the force of the sun’s gravity on the earth?

Explain why the sun’s attraction affects the motion of the earth more than the earth’s attraction affects the sun’s motion. Employ Newton’s second and third laws in your answer.
Physics
1 answer:
Nady [450]3 years ago
5 0

Answer:

The first statement is false, the Sun has a stronger gravitational pull.

:

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how did the ice age affect the landscape of snowdonia? explain whether this process happened over short or a long period of time
nignag [31]

Answer:

It took over a long period of time to form the ice age. During the last Ice age, a thick sheet of the ice covered the landscape of Snowdonia.

The ice sheets shifted downwards and the rock from the back of the valley deposited the material again because the glaciers melted.

The main influence has been the climate and human actions in Snowdonia. The ice age formed around 450 million years ago over the Ordovician period.

6 0
3 years ago
Read 2 more answers
To take off from the ground, an airplane must reach a sufficiently high speed. The velocity required for the takeoff, the takeof
BlackZzzverrR [31]
<h2>Answer: 26,8 s</h2>

Explanation:

If we are talking about an acceleration at a constant rate , we are dealing with constant acceleration, hence we can use the following equations:

{V_{f}}^{2}={V_{o}}^{2}+2ad (1)

V_{f}=V_{o}+at (2)

Where:

V_{f} is the final velocity of the plane (the takeoff velocity in this case)

V_{o}=0 is the initial velocity of the plane (we know it is zero because it starts from rest)

a=5m/s^{2} is the constant acceleration of the plane to reach the takeoff velocity

d=1800m is the distance of the runway

t is the time

Knowing this, let's begin with (1):

{V_{f}}^{2}=0+2(5m/s^{2})(1800m) (3)

{V_{f}}^{2}=18000m^{2}/s^{2} (4)

V_{f}=134.164 m/s (5)

Substituting (5) in (2):

134.164 m/s=0+(5m/s^{2})t (6)

Finding t:

t=26.8 s This is the time needed to take off

6 0
3 years ago
calcular la longitud de un péndulo que oscila a 10 Hz en santa fe de bogota, sabiendo que en esta ciudad la aceleracion de la gr
cricket20 [7]

Answer:

L=2.48*10^{-3} m

Explanation:

The period equation for a pendulum is given by:

T=2\pi \sqrt{\frac{L}{g}}

and we know that T = 1/f, where f is the frequency, so we will have:

\frac{1}{f}=2\pi \sqrt{\frac{L}{g}}

Now, we just need to solve this equation for L.

\frac{1}{2\pi f}=\sqrt{\frac{L}{g}}

L=\frac{g}{(2\pi f)^{2}}

  • g is the gravity in Bogota (g=9.78 m/s^{2})
  • f is 10 Hz
  • L is the lenght of the pendulum

L=\frac{9.78}{(2\pi*10)^{2}}

L=2.48*10^{-3} m

I hope it helps you!

5 0
3 years ago
I would like to know how can I practice physics grade 10 questions?​
Vanyuwa [196]

Answer:

Go to K.han Academy and look up High School Physics on there. Other than that You.Tube has some physics curriculums which probably have practice questions. If not you could just pause the video and see if you can answer the questions they're going over yourself. Also, searching up "Physics Worksheet" and such may help.

6 0
2 years ago
What is the name of the variable that you can change in an experiment?
Schach [20]
That would be the independent variable.

Dependent variable changes according to the independent variable

I honestly don’t know about graphing and stable variables never heard of it before
7 0
3 years ago
Read 2 more answers
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