Answer:b
Explanation:
if your doing it on stemscopes
<u>Given:</u>
Dimensions of the room= 12 ft * 15 ft * 8.60 ft
<u>To determine:</u>
The amount of HCN that gives the lethal dose in the room with the given dimensions
<u>Explanation:</u>
As per the World Health Organization, the lethal dose of HCN is around 300 ppm
300 ppm = 300 mg of HCN/ kg of inhaled air
Volume of air = volume of room = 12 * 15 *8.6 = 1548 ft³
Now, 1 ft³ = 28316.8 cm³
Therefore, the calculated volume of air corresponds to:
1548 * 28316.8 = 4.383 * 10⁷ cm3
Density of air (at room temperature 25 C) = 0.00118 g/cm3
Thus mass of air corresponding to the calculated volume is
Mass = Density * volume = 0.00118 g/cm3 * 4.383 * 10⁷ cm3
= 5.172*10⁴ g = 51.72 kg
Lethal amount of HCN corresponding to 51.72 kg of air would be.
= 51.72 kg air* 300 mg of HCN/1 kg air = 15516 mg
Ans: Lethal dose of HCN = 15.5 g
Answer:
HCN - Hydrogen cyanide The conjugate acid of CN- is HCN. HCN stands for hydrogen cyanide. The conjugate acids are a combination of a strong acid and a low base.
Answer:
<h2>The answer is 1.99 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of acid = 60.19 g
volume = 30.2 mL
The density is
We have the final answer as
<h3>1.99 g/mL</h3>
Hope this helps you
Answer:
In the order appearing in the question: 4, 1 and 1.
Explanation:
The stoichiometry of the conversion of pyruvate into CO2 shows that 1 mol of pyruvate also yields 4 moles of NADH, 1 mol of FADH2 and 1 mol of ATP.