So,
Let x represent Joe's weight and y represent Jeff's weight.
"Joe weighs 20 lbs. less than twice Jeff's weight."
x = 2y - 20
"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
(y + 10) + x = 250
We now have our two open sentences.
x = 2y - 20
(y + 10) + x = 250
Get rid of parentheses.
x = 2y - 20
x + y + 10 = 250
We will use Elimination by Substitution.
2y - 20 + y + 10 = 250
Collect Like Terms.
3y - 10 = 250
Add 10 to both sides.
3y = 260
Divide both sides by 3.
Substitute again.
Multiply.
Subtract.
Check.
"Joe weighs 20 lbs. less than twice Jeff's weight."
Jeff's weight times two is 173 and one-third.
20 lbs. less than that is 153 and one-third lbs. Check.
"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
86 and two-thirds + 10 = 96 and two-thirds.
96 and two-thirds + 153 and one-third equals 250 lbs. Check.
Answer:
Step-by-step explanation:
Look for the GCF and then divide every term by the GCF to see what remains
(9) 5a - 25 ( GCF is 5 so take out 5 and divide every term by 5)
5(a-5)
(10) 28 - 7x ( GCF is 7 so take out 7 and divide every term by 7)
7(4-x)
(11) 12z + 28 - 7z - 3= (combine terms) =
5x+25( GCF is 5 so take out 5 and divide every term by 5)
5(x+5)
Answer/Step-by-step explanation:
A.
Using b = 2
Using b = 4
Using b = 6
Using b = 8
Using b = 10
Using b = 2
B.
Using x = 3
Using x = 5
Using x = 7
Using x = 9
Using x = 11
Using x = 13
C.
Using a = 2
Using a = 3
Using a = 4
Using a = 5
Using a = 6
Using a = 7
D.
Using y = 2
Using y = 3
Using y = 5
Using y = 10
Using y = 8
Using y = 6
Answer:
110
Step-by-step explanation:
Suppose lines EH and BD are parallel:
Angle <GFE and angle <ABC are supplementary so their sum is equal to 180
2x + 10 + x + 20 = 180 add like terms
3x + 30 = 180 subtract 30 from both sides
3x = 150 divide both sides by 3
x = 50
We are asked the value of <ACD
<ABD and <ACD are also supplementary so we can find the value od <ACD:
x + 20 + <ACD = 180 we know x = 50 so we can replace x with that
50 + 20 + <ACD = 180
70 + <ACD = 180 subtract 79 from both sides
<ACD = 110
Okay so there are 52 weeks in a year and she runs 12 miles every week so multiply 52 times 12 which equals 624