$(\stackrel{x_1}{2}~,~\stackrel{y_1}{k})\qquad (\stackrel{x_2}{4k}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{k}}}{\underset{run} {\underset{x_2}{4k}-\underset{x_1}{2}}}~~= ~~\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{2}} \\\\\\ 10-2k=4k-2\implies 10=6x-2\implies 12=6k\implies \cfrac{12}{6}=k\implies 2=k$

5 0

2 years ago

(9x+13)^2=49 Solve the quadratic equation given below.

Varvara68 [4.7K]

Answer:

x=(-2/3)

Step-by-step explanation:

(9x+13)^2=49

√(9x+13)^2=√49

9x+13=7

9x+13-13=7-13

9x=-6

9x÷9=-6/9

x=-6/9

-6/9=-2/3

3 0

3 years ago

Jody can swim one length of the pool in 3 4ths of a minute.how long will it take jody to swim six lengths of the pool

Ostrovityanka [42]

I believe that it is eight minutes

4 0

3 years ago

Joseph is building a cone using modeling clay. The cone has a radius of 6 cm and a height of 12 cm. Joseph adds additional clay,

dmitriy555 [2]

Cone Volume = (π • r² • h) ÷ 3

Original cone = (3.14 * 6^2 * 12) / 3

Original cone = 452.16 cc

Larger cone = (3.14 * 6^2 * 18) / 3 = 678.24 cc

Difference = (678.24 -452.16) = 226.08 cc

3 0

3 years ago

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