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ozzi
4 years ago
12

I need help with this question plzzzzzzzz

Mathematics
1 answer:
mina [271]4 years ago
6 0

Answer:

Your answer is A.

Step-by-step explanation:

If you take the Cords of 'A' and make them both negative you will find your answer.

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a manufacturer has 3375 yards of material on hand. if the average dress takes 3 3/8 yards of material, how many dresses can he m
shepuryov [24]
We know that

3 3/8-------------> (3*8+3)/8-----------> 27/8 yd

if 1 dress take---------------> 27/8 yd
  X-----------------------------> 3375 yd
X=3375/(27/8)---------> x=1000 dresses

the answer is
He can make 1000 dresses
7 0
3 years ago
g find the 2 components of vector b = 2i + j - 3k, one parallel to a = 3i - j and another one perpendicular to a
nika2105 [10]

Answer:

The components of \vec{b} parallel and perpendicular to \vec {a} are \vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j and \vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k, respectively.

Step-by-step explanation:

Let be \vec b = 2\,i+j-3\,k and \vec a = 3\,i-j, the component of \vec b parallel to \vec a is calculated by the following expression:

\vec b_{\parallel} = (\vec b \bullet \hat{a}) \cdot \hat{a}

Where \hat{a} is the unit vector of \vec a, dimensionless and \bullet is the operator of scalar product.

The unit vector of \vec a is:

\hat{a} = \frac{\vec {a}}{\|\vec a\|}

Where \|\vec {a}\| is the norm of \vec a, whose value is determined by Pythagorean Theorem.

The component of \vec{b} parallel to \vec {a} is:

\|\vec {a}\| = \sqrt{3^{2}+(-1)^{2}+0^{2}}

\|\vec {a}\| = \sqrt{10}

\hat{a} = \frac{1}{\sqrt{10}} \cdot (3\,i-j)

\hat{a} = \frac{3}{\sqrt{10}}\,i -\frac{1}{\sqrt{10}} \,j

\vec{b}\bullet \hat{a} = (2)\cdot \left(\frac{3}{\sqrt{10}} \right)+(1)\cdot \left(-\frac{1}{\sqrt{10}} \right)+(-3)\cdot \left(0\right)

\vec b \bullet \hat{a} = \frac{5}{\sqrt{10}}

\vec b_{\parallel} = \frac{5}{\sqrt{10}}\cdot \left(\frac{3}{\sqrt{10}}\,i-\frac{1}{\sqrt{10}}\,j  \right)

\vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j

Now, the component of \vec {b} perpendicular to \vec{a} is found by vector subtraction:

\vec{b}_{\perp} = \vec {b}-\vec {b}_{\parallel}

If \vec b = 2\,i+j-3\,k and \vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j, then:

\vec{b}_{\perp} = (2\,i+j-3\,k)-\left(\frac{3}{2}\,i-\frac{1}{2}\,j  \right)

\vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k

4 0
3 years ago
What is the surface area of the outside of a cube shaped closed-top water tank whose edge length is 7.2 ft? A.373.25 B.311.04 C.
sertanlavr [38]
We know, Surface area of a Cube = 6a²

Substitute for a = 7.2

Then, SA = 6 * (7.2)²

SA = 6 * 51.84 = 311.04 Ft²

In short, Your Answer would be Option B

Hope this helps!
3 0
4 years ago
A bag contains 5 red marbles , 6 blue marbles and 4 green marbles. Susie selects a marble and returns it to the bag before selec
gogolik [260]
Whilst it seems an unlikely scenario, unless we have reason to believe Susie is not making a random choice but is making a free selection, then the previous withdrawals make no difference as the marble is returned each time. Therefore the probability is the same as at the beginning which is 5 red / 15 total marbles, or 1 in 3.
3 0
4 years ago
Laila read 36 pages in 4 hours. Which expression can be used to find the number of pages she read per hour?
MatroZZZ [7]
The last one sounds like the best one to me
3 0
3 years ago
Read 2 more answers
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