Answer:
Compression in the spring, x = 0.20 m
Explanation:
Given that,
Spring constant of the spring, k = 490 N/m
Mass of the block, m = 5 kg
To find,
Compression in the spring.
Solution,
Since the block is suddenly dropped on the spring gravitational potential energy of block converts into elastic potential energy of spring. Its expression is given by :
Where
x is the compression in the spring
x = 0.20 m
So, the compression in the spring due to block is 0.20 meters.
Answer:
A. External
Explanation:
External stimulus includes touch/pain, vision, smell, taste, and sound.
Answer:
The buoyant force experienced by a body is equal to product of unit weight of liguid in which the the objevt is immersed and the volume of liquid replaced by the object.
In the given scenario, bothe the spheres have equal volume and are fully submerged in water. Therefore, the buoyant force experienced by both the spheres will be equal.
1. One
2. Oohm
Hope this helps
Answer:
acceleration = -0.042 m/s²
velocity at beginning = 14.167 m/s
velocity at end = 5.7183 m/s
Explanation:
given data
distance d1 = 1 km
distance d2 = 2 km
time t1 = 80 s
time t2 = 120 s + 80s = 200 s
to find out
acceleration and velocity at beginning and end
solution
we apply here law of motion that is
d = vt + 1/2×at²
put value
1000 = v(80) + 1/2×a(80)² ........................1
and
2000 = v(200) + 1/2×a(200)² ........................2
so from equation 1 and 2 we get a and v
a = -0.042 m/s² and
v = 14.167 m/s
so by kinematic final velocity will be
V² = v² + 2ad
V² = (14.167)² + 2×(-0.042)×(2000)
V² = 32.70
V = 5.7183 m/s
so
acceleration = -0.042 m/s²
velocity at beginning = 14.167 m/s
velocity at end = 5.7183 m/s
